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3 years ago

Twice a number, decreased by 4, is at least 12. A.8 B.7 C.6 D.5

Mathematics

1 answer:

podryga [215]3 years ago

3 0

Not sure if im right but pretty sure it’s 8 because 8*2 is 16-4=12

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Solve the equation for x 80 = 5x + 2x -10

Setler79 [48]

Answer:

x= 12.857

Step-by-step explanation:

80=5x + 2x -10 combine like terms

80= 7x -10 distributed 10 to both sides

90 =7x divide both sides by 7

12.857 =x

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3 years ago

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IF A = [5, 6, 7] and B = [7, 8, 9] then A ∪ B is equal to

Zielflug [23.3K]

Answer:

=[5,6,7,8,9]

Step-by-step explanation:

a=(5,6,7)

B=(7,8,9)

AUB=(5,6,7)U(7,8,9)

=[5,6,7,8,9]

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3 years ago

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How would you write the following expression as a sum or difference? `"log"(root(3)(2 - x)/(3x))`

pashok25 [27]

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

7 0

3 years ago

What is 64x64? and I know if you use a calculator =)

Savatey [412]

Answer:

4096

Step-by-step explanation:

7 0

3 years ago

What is the value of A when we rewrite<br> (5/2)^x +(5/2)^x+3 as A x (5/2)^x

elixir [45]

Answer:

Step-by-step explanation:

$(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]$

Therefore,

$A=1+(\frac{5}{2})^{3}$

3 0

3 years ago