Answer:
Step-by-step explanation:
Part A
Since, the given angles are formed at a point are on a straight line, sum of these angles will be 180°.
Part B
(3x - 5)° + (4x + 2)° + (2x + 3)° = 180°
9x = 180
x = 20
Part C
m∠ADB = (3x - 5)°
= (3×20 - 5)°
= 55°
m∠DBK = (4x + 2)°
= (4×20 + 2)°
= 82°
m∠KBC = (2x + 3)°
= (2×20 + 3)°
= 43°
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])