Identify the type of function below. F(x) = 4x + 2

Mario worked from 8:25 to 12:45 yesterday.Today he will work 11:20 to 3:10. How many hours did he work in all?

Vesnalui [34]

Answer:

Mario worked from

8:25 to 12:45 yesterday

11:20 to 3:10 today

To find the total time of work

12:45

-8:25

_____

4:20

again

11:20

-3:10

______

8:10

Therefore

4:20 + 8:20 = 12 hours 30 min

7 0

3 years ago

How much deeper is the deepest canyon on mars than the deepest canyon on venus

djverab [1.8K]

I googled it and the answer is 1,800 miles

6 0

3 years ago

Read 2 more answers

Explain how the value of the 7 in 327,902 will change if you move it to the tens place

rjkz [21]

It will change from having a value of 7,000 to having a value of 70

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%28a%20%2B%205%29%20-%203%28a%20%2B%207%29%20" id="TexFormula1" title="2(a + 5) - 3(a + 7) "

Kazeer [188]

Answer:

The solutions are given below:

Step-by-step explanation:

x(x-3)+4(x²+2)

= x²-3x+4x²+8

= x²+4x²+8-3x

= 5x²+8-3x

2(a+5)-3(a+7)

= 2a+10-3a-21

= 2a-3a+10-21

= -a-11

xy(x²yz-xy²z+xyz²)

= x³y²z-x²y³z+x²y²z²

-4(a²-2a+8)

= -4a²+8a-32

<h3>Hope it helps !</h3>

8 0

3 years ago

Read 2 more answers

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +

timama [110]

Looks like your function is

$f(x)=\dfrac x{6x^2+1}$

Rewrite it as

$f(x)=\dfrac x{1-(-6x^2)}$

Recall that for $|x|$ , we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

If we replace $x$ with $-6x^2$ , we get

$f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}$

By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2$

Solving for $x$ gives the interval of convergence,

$|x|^2$

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0

3 years ago