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Minchanka [31]
3 years ago
6

Disorder of the particles of a liquid decreases the freezing point. True or false

Chemistry
1 answer:
Gnoma [55]3 years ago
4 0
I think its the answer is true
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Calculate the number of moles of C2H6 in 6.29×1023 molecules of C2H6.
Kipish [7]

1.05moles

Explanation:

Given parameters:

Number of molecules of C₂H₆ = 6.29 x 10²³molecules

Unknown:

Number of moles = ?

Solution:

The mole is the amount of substances that contains Avogadro's number of particles i.e 6.02 x 10²³

 To find the number of moles:

  number of moles = \frac{number of particles}{Avogadro's number}

  number of moles = \frac{6.29 x 10^{23} }{6.02 x 10^{23} }

  number of moles = 1.05moles

Learn more:

moles brainly.com/question/1841136

#learnwithBrainly

7 0
3 years ago
Please help with these questions ASAP will give brainlist!! CHEMISTRY
Irina18 [472]

Answer:

Question 1 is 21.0g

Explanation:

50 x 4.18 x 3.1 / 0.444 / 69.6= 21.0

4 0
3 years ago
Which element forms a chloride of the type XCl2
Nat2105 [25]

Explanation:

Element X forms a chloride with the formula XCl 2 , which is a solid with a high melting point. X would most likely be in the same group of the Periodic Table as. (a) Na (b) Mg (c) Al (d) Si. the answer is Mg .

8 0
3 years ago
A reasonable pka for a weak base is:<br><br> 10.3<br><br> 0.9<br><br> 5.8<br><br> 7.4<br><br> 13.1
andriy [413]

Answer:

0.9

Explanation:

The pka represents the force by which the molecules need to dissociate for the acids ,

Hence , lower the pka stronger will be the acid and that therefore will  dissociate completely and vice versa , for a weak acid higher the pka .

And in case of a base , it will be completely reversed , lower pKa , weaker base ,

and higher pKa , stronger base .

From the data of the question ,

0.9 is the lowest value of the pKa , hence , weakest base .

7 0
3 years ago
I don't know which one it is!
ch4aika [34]
It's what you put :) 
ΔH is the distance from the reactants (which would be E), to the products (which would be G or D)
4 0
3 years ago
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