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iris [78.8K]
3 years ago
10

How many half-lives have passed when there are 3 times as much daughter isotope as parent isotope?

Chemistry
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

2 half lives.

Explanation:

Suppose there are 100g of parent isotope at the start.

After 1 half-life  there will be 50g of parent and 50g of daughter isotope.

After another half life there is  25 g of parent and 75g of daughter isotope.

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Manganese(IV) oxide is reduced to manganese(II) oxide by hydrogen gas. Include all phases in answer
liq [111]
<span><span>Mn<span>O<span>2<span>(s)</span></span></span>+<span>H<span>2<span>(g)</span></span></span>→Mn<span>O<span>(s)</span></span>+<span>H2</span><span>O<span>(g)</span></span></span></span>
4 0
3 years ago
En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber
max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

5 0
3 years ago
2C_H. + 702 — 400, + 6H2O
astra-53 [7]

Balanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume  

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be  

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

hope this helps

6 0
3 years ago
What is the relationship between metals and the number of electrons in the outer level?
gayaneshka [121]
Elements in group 1-2, 13-18, the number of valence electrons is related to the group number. For example, in the first group, the alkali metals there is one valence electron, however in group 13, there are 3 valence electrons. Valence electrons are also known as the outershell electrons.
4 0
3 years ago
One of the earliest atomic models was suggested by John Dalton in the early 1800s.
Nonamiya [84]

Answer:

D. Atoms are like solid balls

Explanation:

John Dalton proposed that all matter is composed of very small things which he called atoms. This was not a completely new concept as the ancient Greeks (notably Democritus) had proposed that all matter is composed of small, indivisible (cannot be divided) objects. When Dalton proposed his model electrons and the nucleus were unknown.

7 0
3 years ago
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