Answer:
1.) The nitric acid solution will oxidize and thus dissolve _*(Zn and Pb)*_. This will allow to identify _**Pt**_.
2) To distinguish between _*(Zn and Pb)*_, we can use the nickel nitrate.
3) The nickel nitrate solution will oxidize and thus dissolve _**Zn**_ and will not oxidize or dissolve _**Pb**_.
Explanation:
1) Unlike Zinc and Lead, Platinum does not react with Nitric acid. So, it will be the only metal from step 1 that doesn't react. Pt is identified in this manner.
2) Nickel is higher than Lead in the activity series, but Zinc is higher than both of them in the activity series. This selectivity can be used to distinguish between Zinc and Lead metal powders.
3) Because Zinc is higher than Nickel in the activity series, it means that Zinc metal can and will displace Nickel from Nickel Nitrate solution. Therefore the Nickel Nitrate solution will oxidize and dissolve the Zinc metal.
But, there will be no reaction with the Lead metal powders sample as Pb is lower than Ni in the activity series, so, Nickel Nitrate solution will not oxidize or dissolve the Lead metal powders.
Answer:
C
Explanation:
Hope this helps Mrs. or Sir
Answer:
Mass = 0.6 g
Explanation:
Given data:
Moles of NaOH = 0.015 mol
Mass of NaOH = ?
Solution:
Number of moles = mass/ molar mass
by rearranging this formula,
Mass = number of moles × molar mass
Molar mass of NaOH is 40 g/mol
by putting values,
Mass = 0.015 mol × 40 g/mol
Mass = 0.6 g
The balanced equation
for the reaction is:
6 HNCO(l) →
C3N3(NH2)3(l) + 3 CO2(g)
Convert amount of urea
from kg to moles
Molar Mass of urea = 60.06
g/mol so, 113 kg urea contains
113 kg / 60.06 = 1.88
mol urea
From balanced equation 6
moles of urea yields only 1 melamine, so divide the moles of urea by 6.
1.88 / 6 = 0.313 kmol
melamine
Now multiply 0.313 with
molar mass of melamine that is 126 g/mol
126 x 0.313 = 39.438 kg
Yield of overall
reaction is 73% so multiply 39.438 with 0.73
<span>39.438 x 0.73 = 28.799
kg is the answer</span>
Answer:
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