CxHy + O2 --> x CO2 + y/2 H2O
Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound
Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound
Find the mass of C and H in the compound:
.430mol x 12 = 5.16 g C
.166mol x 1g = .166g H
When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.
Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).
In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).
Answer:
An electron is around 1800 times smaller than a proton
Explanation:
2HCl (aq) + Zn²⁺ ⇒ ZnCl₂ + 2H⁺ Total Reaction
Leo goes Ger (Lose electron oxidize, Gain electron reduction)
Zn²⁺ + 2e⁻ ⇒ Zn Oxidation half-reaction
2H ⇒ 2H⁺ + 2e⁻ Reduction half-reaction
Answer:
A) secondary amide
Explanation:
When carboxylic acid reacts with a primary amine, a condensation reaction takes place with the elimination of a water molecule .
For example, ethanol reacts with methylamine which is a primary amine gives N-Methylacetamide and a water molecule as:
The bond formed which is
O
||
-- C ---NH ---
is known as secondary amide group as only one hydrogen is attached to nitrogen atom in the amide bond.
Answer:
Potassium (K):
⇒ 39.10 g/mol
Osmium (Os):
⇒ 190.23 g/mol
Manganese (Mn):
⇒ 54.94 g/mol
Explanation:
I Just Did The Assignment
