1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ArbitrLikvidat [17]
3 years ago
13

How could you use these solutions to determine the identities of each metal powder?

Chemistry
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

1.) The nitric acid solution will oxidize and thus dissolve _*(Zn and Pb)*_. This will allow to identify _**Pt**_.

2) To distinguish between _*(Zn and Pb)*_, we can use the nickel nitrate.

3) The nickel nitrate solution will oxidize and thus dissolve _**Zn**_ and will not oxidize or dissolve _**Pb**_.

Explanation:

1) Unlike Zinc and Lead, Platinum does not react with Nitric acid. So, it will be the only metal from step 1 that doesn't react. Pt is identified in this manner.

2) Nickel is higher than Lead in the activity series, but Zinc is higher than both of them in the activity series. This selectivity can be used to distinguish between Zinc and Lead metal powders.

3) Because Zinc is higher than Nickel in the activity series, it means that Zinc metal can and will displace Nickel from Nickel Nitrate solution. Therefore the Nickel Nitrate solution will oxidize and dissolve the Zinc metal.

But, there will be no reaction with the Lead metal powders sample as Pb is lower than Ni in the activity series, so, Nickel Nitrate solution will not oxidize or dissolve the Lead metal powders.

You might be interested in
My labmate discovered a new compound and wanted to try to determine what it could be. We noticed that when mixed with an acid, i
kvv77 [185]

Answer:

it went under the process known as crystalization

Explanation:

am a chemist

4 0
3 years ago
There are two reactants
Xelga [282]

Answer:

13g

Explanation:

The law of conversation of matter tells us that in a chemical reaction, matter is never created or destroyed, it's simply converted from one form to another. So the mass of reactants should always equal the mass of the products in a chemical reaction.

Therefore, if the total mass of the products is 30g, that means that the reactants have a mass of 17g + the other reactant to = 30g.

30g - 17g = 13g

4 0
3 years ago
Examples and connections to the word: Digital. Will give brainliest. 3 for each!
Olenka [21]

Answer: I think this is what your working for.

Examples of digital media include software, digital images, digital video, video games, web pages and websites, social media, digital data and databases, digital audio such as MP3, electronic documents and electronic books.

4 0
3 years ago
Read 2 more answers
Ammonification is the formation of
Vesna [10]
Ammonification refers to chemical reactions in which amino groups (NH2) associated with organic forms of nitrogen are converted into ammonia (NH3) or ammonium (NH4+).
7 0
3 years ago
What is the reaction for CL^2 + 2 KBr —> 2 KCL+Br^2 of 11 grams of potassium bromide?
mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

          11.0g (given)

          0.0924 mol

Cl₂

           0.0462 mol

           3.28g

KCl

           0.0924 mol

           6.89 g

Br₂

         0.0462 mol

         7.39 g

         

Explanation:

<u>1. Balanced chemical equation (given)</u>

   Cl_2+2KBr\rightarrow 2KCl+Br_2

<u>2. Mole ratios</u>

     \dfrac{1molCl_2}{2molKBr}

      \dfrac{2molKCl}{2molKBr}

     \dfrac{1molBr_2}{2molKBr}

<u />

<u>3. Molar masses</u>

  • Molar mass Cl₂: 70.906g/mol
  • Molar mass KBr: 119.002 g/mol
  • Molar mass KCl: 74.5513 g/mol
  • Molar mass KBr: 159.808 g/mol

<u>4. Convert 11 grams of potassium bromide to moles:</u>

  • #moles = mass in grams / molar mass
  • #mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

<u>5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂</u>

a) Cl₂

       \dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2

        0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2

b) KCl

       \dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl

      0.092435molKCl\times 74.5513g/molKCl=6.89gKCl

c) Br₂

       

         \dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2

         0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2

The final calculations are rounded to 3 sginificant figures.

3 0
4 years ago
Other questions:
  • 67.029g to three significant figures
    15·2 answers
  • What is the name of this alkane?
    10·2 answers
  • Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty fo
    7·1 answer
  • Go'=30.5 kJ/mol
    9·1 answer
  • Mengapakah gelung pemanas di dalam cerek elektrik berada di dasar cerek?​
    12·1 answer
  • A taxi hurries with a costant speed of 84km/h. How far it travel in 5 hour
    11·1 answer
  • Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq)HCl(aq) , as desc
    5·1 answer
  • Which phase change is best described by the following expression:
    10·1 answer
  • Adding copper or magnesium to aluminum creates an alloy that is _____. more flammable than magnesium heavier than steel stronger
    12·2 answers
  • I could really use some help with this question, thank you in advance!​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!