What is the third quartile of this data set 20,21,24,25,28,29,35,37,39,42,44
dezoksy [38]
Answer:
The third quartile would be <u>39</u>.
Step-by-step explanation:
• Since the numbers are already in order, the next step would be to find the median:
- The <u>median</u> is the middle number; found by ordering all data points and picking out the one in the middle.
• The <u>first quartile</u>, is denoted as Q1 and is the middle number that falls between the smallest value of the data set and the median.
- The first quartile would be 24.
• The <u>third quartile</u>, is denoted as Q3 and is the median of the upper half of the data set.
- The third quartile would be 39.
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Let the number be x.
x/3 + 12 = 46
Subtract 12 from both sides and you will get:
x/3 = 34
Multiply both sides by 3:
x = 102
Answer:
A. ⇒ The expression is b + 3
B. ⇒ The expression is 2b - 4
C. ⇒ The Dr's office is closer by 4 miles
Step-by-step explanation:
A.
∵ The distance between Daniel's house and his school is b miles
∵ The swimming pool is 3 miles farther from his school
∴ The distance between Daniel's house and the swimming pool is b + 3
B.
∵ The distance from Daniel's house to his Dr's office is 4 less than twice the distance from home to Daniel's school
∵ The distance between Daniel's house and his school is b
∴ The expression of distance from Daniel's house to his Dr's office is
2b - 4
C.
∵ b = 3
∴ The distance between his house and swimming pool is:
3 + 3 = 6 miles
∴ The distance between his house and Dr's office is:
2(3) - 4 = 2 miles
∴ The Dr's office is closer to Daniel's house than the swimming pool by:
6 - 2 = 4 miles
Answer:
-1.9
Step-by-step explanation:
We have that
<span>log10 E = 4.4 + 1.5<span>M
</span></span>E=<span>the released energy in Joules (J)
M= </span><span>earthquake measures---------- > 3.6
</span>log10 E = 4.4 + 1.5*3.6
log10 E = 9.8----------> E=10^(9.8)= 6.309573444 x10^9 J
<span>
the answer is </span>6.309573444 x10^9 J<span>
</span>
