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Nezavi [6.7K]
3 years ago
5

Find the distance between the two points in simplest radical form. (-5,8) (-8,6)

Mathematics
2 answers:
Tanzania [10]3 years ago
5 0

Answer:

\sqrt{445} cannot be reduced any further, so that's the answer.

Step-by-step explanation:

Use the distance formula:

\sqrt{(x2-x1)^{2} +(y2-y1)^{2}} \\\\\sqrt{(-8-10)^{2}+(6--5)^{2}}\\\\\sqrt{(-18)^{2}+(11)^{2}}\\\\\sqrt{(324)+(121)}\\\\= \sqrt{445}\\

mezya [45]3 years ago
5 0
445, the person above is correct
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-17xy + 5x - (-25xy) - 5x
poizon [28]

-17xy+5x-(-25xy)-5x=-17xy+5x+25xy-5x\\\\\text{combine like terms}\\\\=(-17xy+25xy)+(5x-5x)=8xy

3 0
3 years ago
Math help please and don’t look at the top right whatever you do!
Serggg [28]

Answer:

87.88 ft

Step-by-step explanation:

Base x height divided by 2

16.9 ft x 10.4 ft divided by 2 = 87.88 ft

hope this helps:)

8 0
2 years ago
Solve the system:<br> 5x-7y=-41<br> -3x-5y=-3
-Dominant- [34]

Answer:

x = -4 , y = 3

Step-by-step explanation:

5x - 7y = -41 ... (i)

-3x - 5y = -3 ... (ii)

Multiplying (i) by -3 and (ii) by 5 ;

-15x + 21y = 123 ... (i)

-15x - 25y = -15 ... (ii)

Subtracting (i) by (ii) ;

0 + 46y = 138

46y = 138

y = 138 ÷ 46 = 3

Returning to equation (ii) ;

-3x - 5(3) = -3

-3x = -3 + 15

-3x = 12

x = -4

8 0
3 years ago
Read 2 more answers
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
Will choose brainliest! Please help! (This is Khan Academy)
NeTakaya

Answer:

Option B. A = (5/6)^-⅛

Step-by-step explanation:

From the question given above, we obtained:

(5/6)ˣ = A¯⁸ˣ

We can obtain the value of A as follow:

(5/6)ˣ = A¯⁸ˣ

Cancel x from both side

5/6 = A¯⁸

Recall:

M¯ⁿ = 1/Mⁿ

A¯⁸ = 1/A⁸

Thus,

5/6 = 1/A⁸

Cross multiply

5 × A⁸ = 6

Divide both side by 5

A⁸ = 6/5

Take the 8th root of both sides

A = ⁸√(6/5)

Recall

ⁿ√M = M^1/n

Thus,

⁸√(6/5) = (6/5)^⅛

Therefore,

A = (6/5)^⅛

Recall:

(A/B)ⁿ = (B/A)¯ⁿ

(6/5)^⅛ = (5/6)^-⅛

Therefore,

A = (5/6)^-⅛

8 0
3 years ago
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