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Aleksandr-060686 [28]
2 years ago
13

Explain in detail molecular behavior from a hot brick to a cold brick

Physics
1 answer:
slava [35]2 years ago
3 0

Answer:

by conduction, or the transfer of energy from matter to adjacent matter by direct contact, without intermixing or flow of any material. by convection, or the transfer of energy by the bulk mixing of clumps of material. In natural convection it is the difference in density of hot and cold fluid which causes the mixing.

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Corey runs a 100-meter race. 7 seconds after the race started Corey is 45 meters from the starting line and reaches his max spee
RUDIKE [14]

Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
  • d (z) = 45 m + 7 \frac{m}{s} * z
  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

v=\frac{distance}{time}

The distance between the 80 meters and the 45 meters is:

distance = 80 m - 45 m = 35 m

and the time it took to reach the 80 meter will be:

time = 12 s - 7 s = 5 s

So, Corey's max speed is

v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

<h3>What is Corey's distance from the starting line</h3>

At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

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2 years ago
When you throw a pebble straight up with initial speed V, it reaches a maximum height H with no air resistance. At what speed sh
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Answer:

Explanation:

Given

Initial speed is u=V

Maximum height of Pebble is H

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u=initial velocity

a=acceleration

s=Displacement

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H=\frac{V^2}{2g}

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for twice the height

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on comparing

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your answer is the letter (b)


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