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Aleksandr-060686 [28]
3 years ago
13

Explain in detail molecular behavior from a hot brick to a cold brick

Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

by conduction, or the transfer of energy from matter to adjacent matter by direct contact, without intermixing or flow of any material. by convection, or the transfer of energy by the bulk mixing of clumps of material. In natural convection it is the difference in density of hot and cold fluid which causes the mixing.

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A child in a boat throws a 5.3 kg package out horizontally with a speed of 10.0m/s. calculate the velocity of the boat immediate
seropon [69]
<span>(Momentum is Zero) 0 = (26.0 kg + 55.0 kg)v + (5.40 kg)(+10.0 m/s)
</span>velocity = -.667 m/s
5 0
3 years ago
Read 2 more answers
An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
Marysya12 [62]

When air is blown into the open pipe,

L = \frac{nλ}{2}

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=\frac{2L} {n}

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ=\frac{(2)*(6)}{4} =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= \frac{c}{λ}

⇒f=\frac{344}{3}

≈115 Hz

8 0
4 years ago
What is the parallel axis theorem and how is it used? Please explain the equation.
Tema [17]

Explanation:

If an object has a moment of inertia I₀ about an axis, then the moment of inertia about a different, parallel axis is I = I₀ + md², where d is the distance between the axes.

For example, consider a horizontal thin rod rotating about a vertical axis passing through its center.  It has mass m and length L.  Its moment of inertia is known to be I = 1/12 mL².

Now consider the same rod, but this time we move the axis of rotation L/2 to the end of the rod.  We can use parallel axis theorem to find the new moment of inertia:

I = I₀ + md²

I = 1/12 mL² + m (L/2)²

I = 1/12 mL² + 1/4 mL²

I = 1/3 mL²

7 0
4 years ago
A 37 kg object has an applied force of 85N [R] acting on it. The coefficient of
Sliva [168]

Answer:

Explanation:

This is quite tricky! You need to do 2 different equations to solve all the parts of this problem. First is finding the acceleration in one dimension, which has an equation of

F - f = ma

where F is the applied Friction,

f is the frictional force acting against F,

m is the mass of the object, and

a is the acceleration of the object (NOT the velocity!)

This is Newton's Second Law expanded on a bit. The sum of the forces working on an object is equal to the object's mass times its acceleration. We have F, but we need f which is found in the equation

f = μF_n which is the coefficient of kinetic friction times the weight of the object. Weight is found in the equation

w = mg where m is mass and g is the pull of gravity. Let's start there and work backwards:

w = 37(9.8) to 2 sig figs so

w = 360N. Now fill that in to find f:

f = (.17)(360) to 2 sig figs so

f = 61. Now for the final answer in the original equation way back up at the top:

85 - 61 = 37a and do the subtraction on the left side first:

24 = 37a and then we divide to 2 sig figs to get

a = .65 m/s/s

Since we are moving in a straight line (as opposed to on an angle) the displacement is found in

d = rt which simply says that the distance an object moves is equal to its rate times the time. Therefore,

d = 2.2(3.4) to 2 sig figs so

d = 7.5 m

6 0
3 years ago
A man stands on a merry-go-round that is rotating at 2.5 rad/s. If the coefficient of static friction between the man’s shoes an
dybincka [34]

Answer:

0.8 m

Explanation:

Draw a free body diagram.  There are three forces:

Weight force mg pulling down,

Normal force N pushing up,

and friction force Nμ pushing towards the center.

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces in the centripetal direction:

∑F = ma

Nμ = m v²/r

Substitute and simplify:

mgμ = m v²/r

gμ = v²/r

Write v in terms of ω and solve for r:

gμ = ω²r

r = gμ/ω²

Plug in values:

r = (10 m/s²) (0.5) / (2.5 rad/s)²

r = 0.8 m

8 0
3 years ago
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