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lawyer [7]
3 years ago
15

If we're interested in knowing the rate at which light energy is recieved by a unit of area on a particular surface, we're reall

y trying to figure out the
Physics
2 answers:
olchik [2.2K]3 years ago
8 0

Explanation:

If we're interested in knowing the rate at which light energy is received by a unit of area on a particular surface, we're really trying to figure out the illuminance of a surface.

The illuminance of a surface describes the quantity of the light received at a surface or emitted by a light. It measures how much light illuminates the  unit of area on a particular surface.

beks73 [17]3 years ago
5 0
Illluminance is the measurement of photometric power. That means, illuminance is the rate of photometric flux that is received by a surface per area. It is usually expressed as a unit of W/m^2. Thus, from the choices, the answer we're looking for is illuminance<span>.</span>
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two forces whose magnitude are in ratio of 3:5 gives a resultant of 35N.if the angle of inclination is 60degree.calculate the ma
nadya68 [22]

Answer:

the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

Explanation:

The computation of the magnitude of the each force is shown below:

Provided that

Ratio of forces = 3: 5

Let us assume the common factor is x

Now

first force =  3x

And, the second force = 5x

Resultant force = 35 N

The Angle between the forces = 60 degrees  

Based on the above information

Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos\theta

35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]

 35 =√ 9x² + 25x² + 15x²    (cos 60° = 0.5)

35 = √49 x²

 x = 5

So, the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

7 0
3 years ago
Wire sizes are often reported using the AWG (American Wire Gauge) system in which smaller diameter wires are said to be of highe
NISA [10]

Answer:

Explanation:

24 - gauge wire , diameter = .51 mm .

Resistivity of copper ρ = 1.72 x 10⁻⁸ ohm-m

R = ρ l / s

1.72x 10⁻⁸ / [3.14 x( .51/2)² x 10⁻⁶ ]

= 8.42 x 10⁻² ohm

= .084 ohm

B )  Current required through this wire

= 12 / .084 A

= 142.85 A

C )

Let required length be l

resistance = .084 l

2 = 12 / .084 l

l = 12 / (2 x .084)

= 71.42 m

6 0
3 years ago
Read 2 more answers
AIR MASSES!!
777dan777 [17]

Answer:

A : hot and moist, maritime tropical

B: cold and dry, maritime polar

C: hot and moist , maritime tropical

D: cold and dry, continental polar

E: hot and moist , maritime tropical

F: cold and dry , maritime polar

Explanation:

Cold air is denser than warm air. The more water vapor that is in the air, the less dense the air becomes. That is why cold, dry air is much heavier than warm, humid air.

Maritime polar (mP) air masses are cool, moist, and unstable. Some maritime polar air masses originate as continental polar air masses over Asia and move westward over the Pacific, collecting warmth and moisture from the ocean. 

Maritime tropical (mT) air masses are warm, moist, and usually unstable.

5 0
3 years ago
What is the direction of acceleration due to gravity​
Paul [167]

Answer:

Negative, because the speed is decreasing.

4 0
2 years ago
Electrons can move between substances ſchree ways. Which of the following can be
Lady bird [3.3K]

Answer:

B.) “Shininess” should be explained as “Light bounces off the moving electrons.”

Explanation:

6 0
3 years ago
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