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Talja [164]
3 years ago
12

A soccer player kicks a ball with a force of 900 newtons. The ball has a mass of 0.5 kilograms. At what rate will the ball accel

erate?
Explain and show work
Physics
1 answer:
Volgvan3 years ago
6 0

Answer:

1800 m/s^{2}

Explanation:

We know this because of Newton's first law, F=ma, which shows us that the force on an object is equal to its mass times the acceleration it recieves. This means that taking our values of 900N and 0.5kg, and plugging them in,

900N=(0.5kg)*(1800m/s^2)

This is honestly a little strange because the force applied and the acceleration seem ridiculous, and a little strange for an answer. Either the values are not meant to be nearly close to reality, or you made a typo.

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Because of the opposing forces on the car like friction because there is no more acceleration 
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What is the smallest part of an element?<br> An atom
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A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ
valentinak56 [21]

Explanation:

The given data is as follows.

                    mass = 0.20 kg

              displacement = 2.6 cm

              Kinetic energy = 1.4 J

       Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

         Total energy = Kinetic energy + spring potential energy

                           = 1.4 J + 2.2 J

                            = 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So,      K.E = Total energy

                = 3.6 J

Also, we know that

                  K.E = \frac{1}{2}mv^{2}_{m}

or,                   v = \sqrt{\frac{2K.E}{m}}

                        = \sqrt{2 \times 3.6 J}{0.2 kg}

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4 0
3 years ago
A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Appr
Ludmilka [50]

Answer:

The pitch that he hears after the truck passes and is moving away is 819.6 Hz.

Explanation:

The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:    

f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}}

Where:

f: is the perceived frequency

f_{0}: is the emitted frequency

v_{s}: is the speed of sound = 340 m/s

v_{o}: is the speed of the observer = 0 (he is not moving)

v_{f}: is the speed of the fire truck

First, we need to find the speed of the fire truck. When it approaches the observer we have:

f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}}

950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}}

v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz}

v_{f} = 25.05 m/s

Hence, the speed of the fire truck is 25.05 m/s.

Now, we can calculate the pitch that the observer hears after the truck passes:

f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}}

f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s}

f = 819.6 Hz

Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.

I hope it helps you!                                                          

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3 years ago
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