All categories

3 years ago

Which is a graph of g(c) = (0.5)x+3^ -4

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

I've attached a graph with this, that's your answer

You might be interested in

What is the slope of the line that passes through the points (-4,2) and (2,-1)

Anettt [7]

Answer:

1/-2 is the slope

Step-by-step explanation:

$\frac{2-(-1)}{-4-2} = \frac{2+1}{-4-2} = \frac{3}{-6} = \frac{1}{-2}$

8 0

3 years ago

Read 2 more answers

Expand:<br><img src="https://tex.z-dn.net/?f=f%28z%29%20%3D%20%20%5Cfrac%7B1%7D%7Bz%28z%20-%202%29%7D%20" id="TexFormula1" title

Monica [59]

Expand f(z) into partial fractions:

$\dfrac1{z(z-2)} = \dfrac12 \left(\dfrac1{z-2} - \dfrac1z\right)$

Recall that for |z| < 1, we have the power series

$\displaystyle \frac1{1-z} = \sum_{n=0}^\infty z^n$

Then for |z| > 2, or |1/(z/2)| = |2/z| < 1, we have

$\displaystyle \frac1{z-2} = \frac1z \frac1{1 - \frac2z} = \frac1z \sum_{n=0}^\infty \left(\frac 2z\right)^n = \sum_{n=0}^\infty \frac{2^n}{z^{n+1}}$

So the series expansion of f(z) for |z| > 2 is

$\displaystyle f(z) = \frac12 \left(\sum_{n=0}^\infty \frac{2^n}{z^{n+1}} - \frac1z\right)$

$\displaystyle f(z) = \frac12 \sum_{n=1}^\infty \frac{2^n}{z^{n+1}}$

$\displaystyle f(z) = \sum_{n=1}^\infty \frac{2^{n-1}}{z^{n+1}}$

$\displaystyle \boxed{f(z) = \frac14 \sum_{n=2}^\infty \frac{2^n}{z^n} = \frac1{z^2} + \frac2{z^3} + \frac4{z^4} + \cdots}$

6 0

2 years ago

Help me find the GCF 93 AND 62

Ilia_Sergeevich [38]

The GCF of 93 and 62 is 31

8 0

4 years ago

Find the inverse please tell me where to put the dots thanks

aev [14]

Answer:

Draw a line segment from (-7, -2) to (3, 8)

See the diagram below.

You do not have to draw the blue dashed line. It's there to show how the points reflect over.

=========================================================

Explanation:

The inverse will have us swap x and y. The point (x,y) becomes (y,x)

The endpoint (-2, -7) becomes (-7, -2)

Also (8,3) moves to (3, 8)

Visually, these points are being reflected over the line y = x to form the inverse. We only need to worry about the endpoints because 2 points is the minimum needed to form a straight line.

Check out the diagram below. The red segment is the inverse. The blue dashed line is the line y = x. You don't have to plot this line as it's just a visual tool to see what's going on. Your teacher likely will only want the red segment.

Since the original segment is parallel to y = x, the inverse is also parallel to the mirror line. All three lines are parallel.