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kirza4 [7]
3 years ago
15

I really need help!

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
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Please and thankyou (:
den301095 [7]

Let's evaluate the ratio test:

\dfrac{a_n}{a_{n-1}}=\dfrac{3^{n+1}}{3n+1}\cdot\dfrac{3(n-1)+1}{3^n}=\dfrac{3\cdot3^n}{3n+1}\cdot\dfrac{3n-2}{3^n} = \dfrac{9n-6}{3n+1}

The limit as n \to\infty of this quantity is 3, which is more than 1. So, the series diverges.

6 0
4 years ago
Help, BRAINLIEST to CORRECT answer!
arlik [135]

Answer:

False

Step-by-step explanation:

Energy stored in an object is potential energy but energy in motion is kinetic energy  

4 0
3 years ago
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Help!!! (Brainlist!!!!!)
alexgriva [62]
I think it’s B if not I can’t tell because I can’t see all the questions .
4 0
3 years ago
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Differentiate between interest and interest rate​
vodka [1.7K]

Answer:

<h3 /><h3><em>Interest:</em></h3>

<em>Interest is the cost of borrowing money, and the money you earn from your savings.</em>

<h3 /><h3><em>Interest rate</em></h3>

<em>Interest rates indicate this cost or return as a percentage of the amount you are borrowing or lending (since you are “lending” your savings to the </em><em>bank)</em>

<h3><em>❤</em><em>◍</em><em> </em><em>jess </em><em>bregoli</em><em> </em><em>◍❤</em></h3>

#<em>k</em><em>e</em><em>e</em><em>p</em><em> </em><em>learning</em><em>!</em><em>!</em>

5 0
3 years ago
Limit as x approaches 0 of csc3x/cotx
jolli1 [7]
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

<span>\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}</span>

6 0
3 years ago
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