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expeople1 [14]
3 years ago
11

Evaluate 3xy²-y³ for x=-1 and y=2.help.​

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0
The answer to this problem is -20
Annette [7]3 years ago
7 0

Step-by-step explanation:

=3xy²-y³

=3(-1)(2)²-(2)³

=3(-1)(4)-(8)

= -12-8

= -20

hope it helps.

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27 because 6*9 is 54,54 divided by 2 is 26
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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers
Alenkinab [10]

Given:

\sigma_A=3

n_A=6

\sigma_B=5

n_B=4

\overline{x}_A=\overline{x}_B

To find:

The variance. of combined set.

Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

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9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

54=\sum (x_i-\overline{x}_A)^2

Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

100=\sum (x_i-\overline{x}_B)^2

Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

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\sigma^2=\dfrac{154}{10}

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7 0
3 years ago
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castortr0y [4]
Substitute what you know y is equal to into the equation:
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Then you can simplify your equation by multiplying both sides by 2 to eliminate the fraction which will give you:

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Add the -4 to the other side to get 8 and subtract the 2x from the 3x so you have:

x = 8    Now solve for y by substituting your value for x into the other equation:
y = 3/2(8) - 2    Simplify by combining your numbers and you get:
y = 10     Check your answer by substituting y and x into the original equation:
(10) = (8) - 2
Correctly done! So your answers are x = 8 and y = 10
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4 years ago
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