1,725 is you answer because you growth rate is 172.5 a year x ten is 1725
<span>21 Bo; 19 Erica,Vote me brainliest
</span>
<h3>
Therefore they are perpendicular.</h3>
Step-by-step explanation:
A equation of line is
y =mx +c
Here the slope of the line is m.
Given equations are
x - 2y = 18
⇔-2y = -x +18
............(1)
and 2x + y = 6
⇔y = -2x +6 ............(2)
Therefore the slope of equation (1) is
= 
Therefore the slope of equation (2) is
= -2
If two lines are perpendicular, when we multiply their slope we get -1.
therefore,
=. (-2) = -1
Therefore they are perpendicular.
Answer:
55
Step-by-step explanation:
To solve the expression, ![\sqrt[3]{\frac{n}{4}} + \frac{n}{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7Bn%7D%7B4%7D%7D%20%2B%20%5Cfrac%7Bn%7D%7B10%7D)
substitute n = 500 and simplify according to order of operations.
![\sqrt[3]{\frac{500}{4} } + \frac{500}{10}\\\\\sqrt[3]{125}+50\\ 5+50\\\\55](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B500%7D%7B4%7D%20%7D%20%2B%20%5Cfrac%7B500%7D%7B10%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B125%7D%2B50%5C%5C%205%2B50%5C%5C%5C%5C55)
Answer:
A
Step-by-step explanation:
This explanation mostly depends on what you're learning right now. The first way would be to convert this matrix to a system of equations like this.
g + t + k = 90
g + 2t - k = 55
-g - t + 3k = 30
Then you solve using normal methods of substitution or elimination. It seems to me that elimination is the quickest method.
g + t + k = 90
-g - t + 3k = 30
____________
0 + 0 + 4k = 120
4k = 120
k = 30
No you can plug this into the first two equations
g + t + (30) = 90
g + t = 60
and
g + 2t - (30) = 55
g + 2t = 85
now use elimination again by multiplying the first equation by -1
g + 2t = 85
-g - t = -60
_________
0 + t = 25
t = 25
Now plug those both back into one of the equations. I'll just do the first one.
g + (25) + (30) = 90
g = 35
Therefore, we know that Ted spent the least amount of time on the computer.
The second method is using matrix reduction and getting the matrix in the row echelon form, therefore solving using the gauss jordan method. If you would like me to go through this instead, please leave a comment.
