Question

Arrange these compounds by their expected boiling point. Highest boiling point Lowest boiling point CH3OH, CH3CI CH4.

Answer 1

Answer: The given compounds are arranged according to decreasing boiling point as $CH_{3}OH > CH_{3}Cl > CH_{4}$.

Explanation:

The temperature at which vapor pressure of a substance becomes equal to the atmospheric pressure is called boiling point.

Stronger is the intermolecular forces present the atoms of a molecule more heat will be required by it to break the bond between its atoms. Hence, more will the boiling point of the molecule.

In $CH_{3}OH$ (methanol), there is hydrogen bonding present which is a stronger force. So, it will have highest boiling point as compared to $CH_{3}Cl$ and $CH_{4}$.

In $CH_{3}Cl$ (chloroform), there is more electronegative atom attached (Cl) is attached to less electronegative atom (C and H). So, electrons are more pulled towards the chlorine atom. So, boiling point of  $CH_{3}Cl$ is more than methane $(CH_{4})$.

Thus, we can conclude that given compounds are arranged according to decreasing boiling point as $CH_{3}OH > CH_{3}Cl > CH_{4}$.