Answer:
c) 0.080 M Al₂(SO₄)₃
Explanation:
Ion [SO₄²⁻] concentration of each solution is:
a) 0.075 M H₂SO₄: <em>[SO₄²⁻] = 0.075M</em>. Because 1 mole of H₂SO₄ contains 1 mole of SO₄²⁻
b) 0.15 M Na₂SO₄: <em>[SO₄²⁻] = 0.15M</em>. Also, 1 mole of Na₂SO₄ contains 1 mole of SO₄²⁻
c) 0.080 M Al₂(SO₄)₃ [SO₄²⁻] = 0.080Mₓ3 =<em> 0.240M</em>. Because 1 mole of Al₂(SO₄)₃ contains 3 moles of SO₄²⁻.
<h3>Thus, the soluion that has the greatest [SO₄²⁻] is 0.080 M Al₂(SO₄)₃</h3>
<u>Answer:</u> The equations are provided below.
<u>Explanation:</u>
Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.
Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.
Water decomposes in the direct current to form hydrogen and oxygen.
Skeleton Equation: ![H_2O(l)\rightarrow H_2(g)+O_2(g)](https://tex.z-dn.net/?f=H_2O%28l%29%5Crightarrow%20H_2%28g%29%2BO_2%28g%29)
Balanced Equation: ![2H_2O(l)\rightarrow 2H_2(g)+O_2(g)](https://tex.z-dn.net/?f=2H_2O%28l%29%5Crightarrow%202H_2%28g%29%2BO_2%28g%29)
Mercury (II) oxide decomposes in heat to form mercury, oxygen.
Skeleton Equation: ![HgO(s)\rightarrow Hg+O_2](https://tex.z-dn.net/?f=HgO%28s%29%5Crightarrow%20Hg%2BO_2)
Balanced Equation: ![2HgO(s)\rightarrow 2Hg+O_2](https://tex.z-dn.net/?f=2HgO%28s%29%5Crightarrow%202Hg%2BO_2)
Calcium carbonate when heated forms calcium oxide and carbon dioxide.
Skeleton Equation: ![CaCO_3(s)\rightarrow CaO(s)+CO_2(g)](https://tex.z-dn.net/?f=CaCO_3%28s%29%5Crightarrow%20CaO%28s%29%2BCO_2%28g%29)
Balanced Equation: ![CaCO_3(s)\rightarrow CaO(s)+CO_2(g)](https://tex.z-dn.net/?f=CaCO_3%28s%29%5Crightarrow%20CaO%28s%29%2BCO_2%28g%29)
Group 2 hydroxides, when heated forms oxide and water vapor.
Skeleton Equation: ![Ca(OH)_2\rightarrow CaO+H_2O](https://tex.z-dn.net/?f=Ca%28OH%29_2%5Crightarrow%20CaO%2BH_2O)
Balanced Equation: ![Ca(OH)_2\rightarrow CaO+H_2O](https://tex.z-dn.net/?f=Ca%28OH%29_2%5Crightarrow%20CaO%2BH_2O)
Cars, aeroplanes, factories etc
This problem is being solved using Ideal Gas Equation.
PV = nRT
Data Given:
Initial Temperature = T₁ = 27 °C = 300 K
Initial Pressure = P₁ = constant
Initial Volume = V₁ = 8 L
Final Temperature = T₂ = 78 °C = 351 K
Final Pressure = P₂ = constant
Final Volume = V₂ = ?
As,
Gas constant R and Pressures are constant, so, Ideal gas equation can be written as,
V₁ / T₁ = V₂ / T₂
Solving for V₂,
V₂ = (V₁ × T₂) ÷ T₁
Putting Values,
V₂ = (8 L × 351 K) ÷ 300 K
V₂ = 9.38 L
Answer:
(C) Oxygen because it has the strongest attractive force and the largest
electronegativity
Explanation:
Oxygen will be most reactive
configuration = ![1s^22s^22p^4](https://tex.z-dn.net/?f=1s%5E22s%5E22p%5E4)
As oxygen need only two electrons to complete its octet.
Oxygen will have stronger force than nitrogen as it will tend to pull electrons more to complete its octet. Also along the period electronegativity increases so oxygen has higher electronegativity than nitrogen