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3 years ago

How many kilowatt hours does it take to lift an apple that weighs 100g 1 meter.(use 9.8 kg

Chemistry

1 answer:

kati45 [8]3 years ago

3 0

Answer:

The answer to your question is Power = 0.98 W or 9.8 x 10⁻⁴ kW

Explanation:

Data

Power = ?

mass = 100 g = 0.1 kg

distance = 1 m

gravity = 9.8 m/s²

Formula

Power = Work / time

Process

1.- Calculate the Work

Work = Force x distance

Force = mass x gravity

Work = mass x gravity x distance

Work = (0.1 kg)(9,8)(1)

Work = 0.98 J

2.- Calculate the power

Power = 0.98 J / 1 h

Power = 0.98 W or 9.8 x 10⁻⁴ kW

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Calculate the EMF between copper and silver Ag+e-E=0.89v<br>Cu=E=0.34v

bogdanovich [222]

Answer:

Depending on the $E^\circ$ value of $\rm Ag^{+} + e^{-} \to Ag\; (s)$ , the cell potential would be:

$0.55\; \rm V$ , using data from this particular question; or
approximately $0.46\; \rm V$ , using data from the CRC handbooks.

Explanation:

In this galvanic cell, the following two reactions are going on:

The conversion between $\rm Ag\; (s)$ and $\rm Ag^{+}$ ions, $\rm Ag^{+} + e^{-} \rightleftharpoons Ag\; (s)$ , and
The conversion between $\rm Cu\; (s)$ and $\rm Cu^{2+}$ ions, $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ .

Note that the standard reduction potential of $\rm Ag^{+}$ ions to $\rm Ag\; (s)$ is higher than that of $\rm Cu^{2+}$ ions to $\rm Cu\; (s)$ . Alternatively, consider the fact that in the metal activity series, copper is more reactive than silver. Either way, the reaction is this cell will be spontaneous (and will generate a positive EMF) only if $\rm Ag^{+}$ ions are reduced while $\rm Cu\; (s)$ is oxidized.

Therefore:

The reduction reaction at the cathode will be: $\rm Ag^{+} + e^{-} \to Ag\; (s)$ . The standard cell potential of this reaction (according to this question) is $E(\text{cathode}) = 0.89\; \rm V$ . According to the 2012 CRC handbook, that value will be approximately $0.79\; \rm V$ .

The oxidation at the anode will be: $\rm Cu\; (s) \to \rm Cu^{2+} + 2\, e^{-}$ . According to this question, this reaction in the opposite direction ( $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ ) has an electrode potential of $0.34\; \rm V$ . When that reaction is inverted, the electrode potential will also be inverted. Therefore, $E(\text{anode}) = -0.34\; \rm V$ .

The cell potential is the sum of the electrode potentials at the cathode and at the anode:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &= 0.89 \; \rm V + (-0.34\; \rm V) = 0.55\; \rm V\end{aligned}$ .

Using data from the 1985 and 2012 CRC Handbook:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &\approx 0.7996 \; \rm V + (-0.337\; \rm V) \approx 0.46\; \rm V\end{aligned}$ .

5 0

3 years ago

In a series circuit, electrons only flow along one path. Given this information, which of the following is an advantage of serie

Ivenika [448]

Answer: D. Series circuits are simpler than parallel circuits.

Explanation:

In series circuit, all the components are connected in single path of current flow.

If one part of the circuit breaks, complete circuit would break and all the other parts also would not operate.

The voltage is not same everywhere. It is different across each component.

In series circuit, net resistance is more as resistance of all the components connected in series are added up.

So, the only advantage of a series circuit is that is simpler than the parallel circuits. Thus, the correct option is D.

3 0

2 years ago

What volume of hydrogen (in L) is produced

scZoUnD [109]

Answer:

5.26

Explanation:

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3 years ago

How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was

NISA [10]

People had asked this many times and that is why they came up with methods and standards that will answer these type of questions. You can look it up in the NIST or the National Institute for Standards and Technology.

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2 years ago

CHEMISTRY OuO Help please

jeka94

Answer:

This is google's answer for the last question

Explanation:

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3 years ago