Question

Relative velocity: An airplane flies between two points on the ground that are 500 km apart. The destination is directly north of the origination of the flight. The plane flies with an air speed of 120 m/s. If a constant wind blows at 10.0 m/s due west during the flight, what direction must the plane fly relative to north to arrive at the destination

Answer 1

Answer:

4.78 degrees east of north

Explanation:

The computation is shown below:

The Speed of the plane is 120 m/s

The Speed of the wind is 10 m/s

Sin $\theta$ = 10 ÷ 120

= 1 ÷ 12

= 0.0833

Now

\theta = 4.78 degrees

It should be 4.78 degrees east of north

Since the wind blows due west plane and it should fly east of north to  reach at the final destination