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mario62 [17]
3 years ago
14

List the requirements of practical fuel?

Physics
1 answer:
rewona [7]3 years ago
7 0

Answer:

Here we have some of the requirement of practical fuel are

1. It must contain large amount of stored energy.  So that more amount of power output available to run the engines, motors etc.    

2.  It must occur in abundance in nature or be easy to produce.  

3. The fuel must be made up of elements that combine easily with oxygen. Foe example if hydrogen molecules reacts with oxygen. Then the products are at the reaction of lower energy than the reactants, the result is the explosive release of energy and the product of water.  


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Lowest frequency?_______​
Sergio039 [100]

Answer:

Radio waves are the lowest frequency

Explanation:

Here is the order of frequencies highest to lowest to help you in the future:

gamma rays

X-rays

ultraviolet radiation

visible light

infrared radiation

radio waves

8 0
3 years ago
How much heat is removed from 60 grams of steam at 100 °C to change it to 60 grams
Harrizon [31]

Answer:

45200J

Explanation:

Given parameters:

Heat of vaporization of water  = 2260J/g

Mass of steam = 20g

Temperature = 100°C

Unknown:

Energy released during the condensation  = ?

Solution:

This change is a phase change and there is no change in temperature

To find the amount of heat released;

         H  = mL

m is the mass

L is the latent heat of vaporization

Insert the parameters and solve;

         H  = 20g x 2260J/g

          H = 45200J

4 0
2 years ago
A very narrow beam of white light is incident at 40.80° onto the top surface of a rectangular block of flint glass 11.6 cm thick
DerKrebs [107]
Dispersion angle = 0.3875 degrees. 
Width at bottom of block = 0.09297 cm 
Thickness of rainbow = 0.07038 cm 
 Snell's law provides the formula that describes the refraction of light. It is:
 n1*sin(θ1) = n2*sin(θ2)
 where
 n1, n2 = indexes of refraction for the different mediums
 Î¸1, θ2 = angle of incident rays as measured from the normal to the surface. 
 Solving for θ2, we get
 n1*sin(θ1) = n2*sin(θ2)
 n1*sin(θ1)/n2 = sin(θ2)
 asin(n1*sin(θ1)/n2) = θ2 
 The index of refraction for air is 1.00029, So let's first calculate the angles of the red and violet rays.
 Red:
 asin(n1*sin(θ1)/n2) = θ2
 asin(1.00029*sin(40.80)/1.641) = θ2
 asin(1.00029*0.653420604/1.641) = θ2
 asin(0.398299876) = θ2
 23.47193844 = θ2 
 Violet:
 asin(n1*sin(θ1)/n2) = θ2
 asin(1.00029*sin(40.80)/1.667) = θ2
 asin(1.00029*0.653420604/1.667) = θ2
 asin(0.39208764) = θ2
 23.08446098 = θ2 
 So the dispersion angle is:
 23.47193844 - 23.08446098 = 0.38747746 degrees. 
 Now to determine the width of the beam at the bottom of the glass block, we need to calculate the difference in the length of the opposite side of two right triangles. Both triangles will have a height of 11.6 cm and one of them will have an angle of 23.47193844 degrees, while the other will have an angle of 23.08446098 degrees. The idea trig function to use will be tangent, where
 tan(θ) = X/11.6
 11.6*tan(θ) = X
 So for Red:
 11.6*tan(θ) = X
 11.6*tan(23.47193844) = X
 11.6*0.434230136 = X
 5.037069579 = X 
 And violet:
 11.6*tan(θ) = X
 11.6*tan(23.08446098) = X
 11.6*0.426215635 = X
 4.944101361 = X 
 So the width as measured from the bottom of the block is: 5.037069579 cm - 4.944101361 cm = 0.092968218 cm 
 The actual width of the beam after it exits the flint glass block will be thinner. The beam will exit at an angle of 40.80 degrees and we need to calculate the length of the sides of a 40.80/49.20/90 right triangle. If you draw the beams, you'll realize that:
 cos(θ) = X/0.092968218
 0.092968218*cos(θ) = X 
 0.092968218*cos(40.80) = X
 0.092968218*0.756995056 = X
 0.070376481 = X 
 So the distance between the red and violet rays is 0.07038 cm.
7 0
3 years ago
in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th
Nata [24]

Answer:

R = 73.25 m

Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

The maximum range of the ball is given by :

R=\dfrac{u^2\sin2\theta}{g}

Plugging all the values we get :

R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m

So, the maximum range of the ball is 73.25 m

8 0
3 years ago
Which of the following STEM discoverers is known for inventing the circular saws used in sawmills? Babbitt Edison Gates Hawking
Jet001 [13]
Among the STEM discoverers, the one who is known for the invention of the circular saws that are used in sawmills is Babbitt or better known as Sarah "Tabitha<span>" Babbitt, an American inventor and Shaker tool maker. The answer to this is the first option. Hope this helps.</span>
5 0
3 years ago
Read 2 more answers
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