Answer:
the index of refraction of the coating is 1.33
Explanation:
Given the data in the question;
refraction index of interior portion of the rod η
= 1.55
angle of incidence θ
= 59.5°
From Snell's law, we know that;
η
× sinθ
= η
× sinθ
where η
is the index of refraction of the rod ( material 1 )
θ
is the angle of incidence
η
is the index of refraction in outer coating ( material 2 )
θ
is the angle of refraction
so we substitute our values into the equation;
η
× sinθ
= η
× sinθ
1.55 × sin( 59.5° ) = η
× sin( 90° )
1.55 × 0.861629 = η
× 1
1.3355 = η
× 1
η
= 1.33 { 2 decimal places }
Therefore, the index of refraction of the coating is 1.33
Answer: [D] (Clarification: The one with the steepest incline)
Carson's Rule says:
FM occupied bandwidth =
(2) · (Peak deviation + Highest modulating frequency)
so
FM bw = (2) · (60 kHz + 15 kHz)
FM bw = (2) · (75 kHz)
FM bw = 150 kHz
(I used to eat this stuff for lunch, but it's been almost 40 years. Thanks for taking me back. Those were the good old days.)
False. Most of the bright stars in our galaxy are located in the disk.