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Reika [66]
3 years ago
5

Hi:) why do metals have free electrons? anyone able to explain the conduction part as well? Thanks!

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Metals have free electrons due to the bonding in metallic substances.

In a metal there are strong attractive forces between the nuclei and the valance electrons.

Positively charged metal nuclei form a lattice (a cube like structure) each metal atom provides one or more valance electrons <u>that are free to move throughout the lattice</u> The electrons are attracted to the positively charged nuclei but not one individual nuclei, this is called non-directional bonding since it occurs in all directions.

Now all metals are conductive becuase of the free to move (delocalised) electrons. Since the valance electrons are free to move throughout the lattice they are able to carry a charge. (Ionic solids cannot since the ionic solids form a tightly packed lattice with cations and anions which have no free moving electrons, electrons have to be able to move to carry a charge)

<u />

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A car’s horn has a frequency of 1000 Hz. An observer hears the
Brut [27]

Answer:

31.4 m/s

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr)/(c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 1000 Hz

fr = 1100 Hz

c = 345 m/s

vr = 0 m/s

Find: vs

1100 = 1000 (345 + 0) / (345 + vs)

vs = -31.4

The speed of the car is 31.4 m/s.

7 0
4 years ago
If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s , determine the constant deceleration of the car
Svetlanka [38]

Question:  Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.

Answer:

1.29 m/s²

Explanation:

From the question,

a = (v-u)/t............................ Equation 1

Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.

Given: v = 13 m/s, u = 35 m/s, t = 17 s.

a = (13-35)/17

a = -22/17

a = -1.29 m/s²

Hence the deceleration of the car is 1.29 m/s²

8 0
3 years ago
A ball is tossed in the air and released. It moves up, reverses direction, falls back down again, and is caught at the same heig
PolarNik [594]

Answer:

The potential energy has a  maximum when the ball is a time that is half of the time for total travel

Explanation:

Generally potential energy is a the varies directly with the height according to this formula

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and the ball attains a maximum height when the time is equal to half of the total time taken to travel  

8 0
3 years ago
Read 2 more answers
A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t
aleksandr82 [10.1K]

Answer:

Acceleration: 9800 ft/s^2

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

t = 0.5 s (time taken)

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Write your answer to the question below.
ElenaW [278]

Answer:

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