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3 years ago

Physics!!! Please help!!!!!!!

Physics

1 answer:

Marianna [84]3 years ago

8 0

Answer:

it is a very good morning amor de g the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of 88th paragraph of the first paragraph

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A woman drives 200 miles west and then turns south and drives 375 miles. Her trip takes her 11.75 hrs. What is the woman's avera

FromTheMoon [43]

Answer:

The woman's average velocity during the trip is 36.2 miles/hour.

Explanation:

Velocity can be define as the displacement of an object per time. It is a vector quantity, and measured in m/s.

i.e velocity = $\frac{displacement}{time}$

From the given question,

Displacement = $\sqrt{200^{2} + 375^{2} }$

= $\sqrt{40000+140625}$

= $\sqrt{180625}$

= 425

The displacement of woman is 425 miles.

velocity = $\frac{425}{11.75}$

= 36.1702 miles/hour

The woman's average velocity during the trip is 36.2 miles/hour.

7 0

3 years ago

What is the difference between gravimetric and volumetric analysis?

Masteriza [31]

Once the presence of certain substances in a sample is known, the study of their absolute or relative abundance can help in determining specific properties. Gravimetric analysis yields more accurate data about the composition of a sample than volumetric analysis but also takes more time to perform in the laboratory.

8 0

3 years ago

A horizontal force of magnitude 46.3 n pushes a block of mass 4.14 kg across a floor where the coefficient of kinetic friction i

IrinaVladis [17]

A) Calling F the intensity of the horizontal force and d the displacement of the block across the floor, the work done by the horizontal force is equal to
$W=Fd = (46.3 N)(4.25 m)=196.8 J$

b) The work done by the frictional force against the motion of the block is equal to:
$W_f = -F_f d =- (\mu mg) d =-(0.609)(4.14 kg)(9.81 m/s^2)(4.25 m)=$
$=-105.1 J$
Part of these 105.1 Joules of work becomes increase of thermal energy of the block ( $\Delta E_B$ ), and part of it becomes increase of thermal energy of the floor ( $\Delta E_F$ ). We already know the increase in thermal energy of the block (38.2 J), so we can find the increase in thermal energy of the floor:
$\Delta E_F = 105.1 J - \Delta E_B = 105.1 J-38.2 J=66.9 J$

c) The net work done on the block is the work done by the horizontal force F minus the work done by the frictional force (the frictional force acts against the motion, so we must take it with a negative sign):
$W_{net}=W-W_f=196.8 J-105.1 J=91.7 J$
For the work-energy theorem, the work done on the block is equal to its increase of kinetic energy:
$W_{net} = \Delta K$
So, we have $\Delta K=+91.7 J$

5 0

3 years ago

A 5 kg object is moving in a straight-line with an initial speed of v m/s. It takes 13 s for the speed of the object to increase

coldgirl [10]

The object's kinetic energy changes according to

dK/dt = 15 J/s

If v is the object's initial speed, then its initial kinetic energy is

K (0) = 1/2 (5 kg) v ²

Use the fundamental theorem of calculus to solve for K as a function of time t :

$K(t) = K(0) + \displaystyle\int_0^t \left(15\frac{\rm J}{\rm s}\right)\,\mathrm du = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)t$