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Anton [14]
3 years ago
7

Ethyl trichloroacetate is significantly more reactive toward hydrolysis than ethyl acetate. Explain this observation. The three

chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group less electrophilic. The three chlorine atoms add electron density via induction. This effect renders the carbonyl group less electrophilic. The three chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group more electrophilic. The three chlorine atoms add electron density via induction. This effect renders the carbonyl group more electrophilic.
Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

The three chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group more electrophilic.

Explanation:

Ethyl trichloroacetate(C4H5Cl3O2) is significantly more reactive towards hydrolysis than ethyl acetate. This is because the three chlorine atoms withdraw electron density via induction and renders the carbonyl group C=O more electrophlic(tendency to attract more electrons).

Hydrolysis is a chemical reaction which involves water molecules being added to a substance.

The increased electrophilic feature enhances its reaction with water.

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Answer:

8.70 liters.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>3O₂ + 4Al → 2Al₂O₃,</em>

It is clear that 3.0 moles of O₂ react with 4.0 moles of Al to produce 2.0 Al₂O₃.

  • Firstly, we need to calculate the no. of moles (n) of 36.12 g of Al₂O₃:

n = mass/molar mass = (36.12 g)/(101.96 g/mol) = 0.3543 mol.

<u><em>using cross multiplication:</em></u>

3.0 mol of O₂ produces → 2.0 mol of Al₂O₃.

??? mol of O₂ produces → 0.3543 mol of Al₂O₃.

∴ The no. of moles of O₂ needed to produce 36.12 grams of Al₂O₃ = (3.0 mol)(0.3543 mol)/(2.0 mol) = 0.5314 mol.

  • Now, we can find the volume of O₂ used during the experiment:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.4 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 0.5314 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 280 K).

∴ V = nRT/P = (0.5314 mol)(0.0821 L.atm/mol.K)(280 K)/(1.4 atm) = 8.726 L ≅ 8.70 L.

<em>So, the right choice is: 8.70 liters.</em>

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