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Anton [14]
3 years ago
7

Ethyl trichloroacetate is significantly more reactive toward hydrolysis than ethyl acetate. Explain this observation. The three

chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group less electrophilic. The three chlorine atoms add electron density via induction. This effect renders the carbonyl group less electrophilic. The three chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group more electrophilic. The three chlorine atoms add electron density via induction. This effect renders the carbonyl group more electrophilic.
Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:

The three chlorine atoms withdraw electron density via induction. This effect renders the carbonyl group more electrophilic.

Explanation:

Ethyl trichloroacetate(C4H5Cl3O2) is significantly more reactive towards hydrolysis than ethyl acetate. This is because the three chlorine atoms withdraw electron density via induction and renders the carbonyl group C=O more electrophlic(tendency to attract more electrons).

Hydrolysis is a chemical reaction which involves water molecules being added to a substance.

The increased electrophilic feature enhances its reaction with water.

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How are a moon and an asteroid different? (2 points)
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B

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3 years ago
How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

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3 years ago
What factors do not affect nuclear reactions, but do affect chemical reaction
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7 0
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Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
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Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:                      

element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

atomic mass:          39.185/31.0 g/mol           60.82/32.0g/mol

                              =1.26mol                           1.90mol

smallest mole ratio:   1.26mol/1.26mol =1      1.90mol/1.26 mol =1.50

multiply with 2:          2                                         3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

=P_4S_6

8 0
3 years ago
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