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Inessa05 [86]
3 years ago
6

Which choice correctly places the discovery of subatomic particles in order from earliest to latest?

Chemistry
1 answer:
xeze [42]3 years ago
7 0
Wait hold up do you live in Wilson county????
You might be interested in
How do alchemy and chemistry differ?
vaieri [72.5K]
In very basic terms alchemy is magic and chemistry is scientific.
6 0
3 years ago
A block of wood has a volume of 64 cm3 and a mass of 46 grams. What is the density of the block?
Rom4ik [11]

The correct answer is 0.72 g/cm3

Explanation:

The density of a material depends on both its mass (amount of matter), which is usually provided in grams (g), and its volume (space occupied), which is provided in units such as cubic centimeters cm3. Moreover, to find how dense the material is, take the mass and divide it into the volume. The process for finding the density of the block of wood is shown below:

d = \frac{m}{v}

d = \frac{46 g}{64 cm3}

d = 0.718 g/cm3

This means the density is 0.71g/cm3 and this can be rounded to 0.72 g/cm3

3 0
3 years ago
The density of a substance is 4.8 g/mL. What is the volume of the sample that is 19.2 g?
mixas84 [53]

Answer:

The answer is 4

Explanation:

You divide the grams by the volume which will give you the density

so 19.2 divided by 4.8 equals 4

5 0
3 years ago
Convert 6.71 moles NH3 to number of molecules.
svetlana [45]

Answer: There are 40.41 \times 10^{23} molecules present in 6.71 moles of NH_{3}.

Explanation:

Given: Moles of NH_{3} = 6.71 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{22} molecules.

Therefore, molecules present in 6.71 moles are calculated as follows.

Molecules = moles \times 6.022 \times 10^{23}\\= 6.71 \times 6.022 \times 10^{23}\\= 40.41 \times 10^{23}

Thus, we can conclude that there are 40.41 \times 10^{23} molecules present in 6.71 moles of NH_{3}.

6 0
3 years ago
I WILL GIVE BRAINLIEST!!!!!
Alexxx [7]
                                    HNO₃ + H₂S → S + NO + H₂<span>O

Assign Oxidation Number:

                                L.H.S                               R.H.S
           N in HNO</span>₃  =  +5                                     +2  =  N in NO
               S in H₂S  =  -2                                       0  =  S in S

Write Half cell Reactions:
Reduction Reaction:
                                 
3e⁻  +   HNO₃   →   NO      -------(1)
Oxidation Reaction:
                                  H₂S   →   S  +  2e⁻             -------(2)

Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons. 

                                          6e⁻  +   2 HNO₃   →   2 NO
                                    
                                             3 H₂S   →   3 S  +  6e⁻
                                                                                  Cancel e⁻s,
                                 ______________________________
                               
                             2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  H₂O

Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.

                            2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  4H₂O


                                
4 0
4 years ago
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