The name is 2-Chloro Propane
Because the chlorine is linked to the second carbon atom when it is spread out
Answer:
10.11 mL
Explanation:
Given that :
Total volume of decolorizer = 500 mL
A common recipe is equal parts 95% ethanol and acetone.
So;
The volume of 95% ethanol in the decolorizer = 500mL/2 = 250 mL
Let represent V(ml) for the 99% of ethanol needed to make 95% of the 250 mL of ethanol;
Therefore:
V(ml) × 0.99 = 250 × 0.95
V(ml) × 0.99 = 237.5
V(ml) = 237.5/0.99
V(ml) = 239.89 mL
Hence; the amount of water to be added to 95% of ethanol = ( 250 - 239.89 )mL = 10.11 mL
The mass of NCl3 in 4.00 moles of NCl3 is 481.44 grams
Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g. The number of particles present in one mole of any substance =Avogadro Number=6.
The formula for number mole is given as:
Number of moles = <u>Mass of the substance </u> ; Now substituting the values
Molar mass
⇒ 4.00 = <u>x </u> [Molar mass of NCl3 = 120.36]
120.36
⇒ x = 4.00 × 120.36
⇒ x = 481.44 grams
Therefore the mass of NCl3 is 481.44 grams
To know more about mole concept
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Answer:
0.06 kg
Explanation:
Given data:
Mass of frisbee = ?
Velocity of frisbee = 11 m/s
Energy of frisbee = 3.6 j
Solution:
K.E = 1/2 mv²
Now we will put the values in this formula.
3.6 J = 1/2 m(11m/s)²
3.6 j = 0.5 ×121m²/s² × m
3.6 j = 60.5 m²/s² × m
m = 3.6 j/60.5 m²/s²
m= 0.06 j.m⁻².s²
j = Kg.m².s⁻²
m= 0.06 Kg.m².s⁻² .m⁻².s²
m = 0.06 kg
Answer:

Explanation:
Step 1: Given data
- Molarity of the HF solution (M): 0.500 M
- Volume of the solution (V): 750.0 mL
Step 2: Convert "V" to liters
We will use the conversion factor 1 L = 1000 mL.
750.0 mL × 1 L/1000 mL = 0.7500 L
Step 3: Calculate the moles of HF
We will use the following expression.
n = M × V
n = 0.500 mol/L × 0.7500 L = 0.375 mol
Step 4: Calculate the atoms of F in 0.375 moles of HF
We will use the following relationships:
- 1 mole of HF contains 1 mole of atoms of F.
- 1 mole of atoms of F contains 6.02 × 10²³ atoms of F (Avogadro's number).
