<u>Answer:</u> The moles of oxygen and carbon dioxide in air is 
and 
respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of atmosphere = 
Average molar mass of atmosphere = 28.96 g/mol
Putting values in above equation, we get:
We know that:
Percent of oxygen in air = 21 %
Percent of carbon dioxide in air = 0.0415 %
Moles of oxygen in air = 
Moles of carbon dioxide in air = 
Hence, the moles of oxygen and carbon dioxide in air is and respectively
Answer:
The atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.
Explanation:
As we travel along a period in a periodic table then the atomic radii decreases
This is because as we travel along a period we have that the atomic number of the atoms increases which means the the number of proton's increased
But the electron's add to the same outer shell throughout the period , which means the effective nuclear charge increases which pulls the outer electrons toward's the nucleus and the size decreases.
Therefore the atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.
Answer:
T₂ = 317.87 K
Explanation:
Given data:
Initial pressure = 15 atm
Final pressure = 16 atm
Initial temperature = 298 K
Final temperature = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
15 atm / 298K = 16 atm/T₂
T₂ = 16atm × 298 K / 15 atm
T₂ = 4768 atm. K / 15 atm
T₂ = 317.87 K
True when the boron control rods are lowered it slows the reaction
I’m pretty sure it’s true
