<h2><u>Question :-</u></h2>
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) Reduced, and the oxidation number changes from +1 to 0.
b) Reduces and the oxidation number changes from +2 to 0.
c) Oxidized and the oxidation number changes from 0 to +1.
d) Oxidized, and the oxidation number changes from +1 to 0.
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<h2><u>Solution :-</u></h2>
<h3><u>Given Information :-</u></h3>
- <u>Reaction ➢</u> Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag
<h3><u>To Find :-</u></h3>
- a) Reduced, and the oxidation number changes from +1 to 0.
- b) Reduces and the oxidation number changes from +2 to 0.
- c) Oxidized and the oxidation number changes from 0 to +1.
- d) Oxidized, and the oxidation number changes from +1 to 0.
<h3><u>Answer :-</u></h3>
Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-
- Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.
- Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.
In this reaction, Ag⁺ gains an electron to get <u>reduced</u> to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.
Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.
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<h2><u>Final Answer :-</u></h2>
- Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.
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