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3 years ago

Pls help will give brainliest when i can

Mathematics

1 answer:

aivan3 [116]3 years ago

4 0

Angle 1 is corresponding to angle 5.
This is where one angle has the same relative position as another angle.

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3x/2 - 2 > 7

KiRa [710]

3x+2/2 = 7. First, multiply 2 to both sides and you get 3x+2=14. Then, just solve using backward PEMDAS. The answer is 4.

8 0

3 years ago

Read 2 more answers

A set of equations is given below:

artcher [175]

Answer:

comparing both equation we get,

2X+1=X+9

or, X=8

Y=X+9

or, Y=17

therefore the required solution is (8,17)

7 0

3 years ago

The equation of a circle centered at the origin is x^2+y^2=16. what is the radius of the circle?

vekshin1

Answer:

The center is (0,0) and the radius is 4

Step-by-step explanation:

x^2+y^2=16.

The equation of a circle can be written in the form

(x-h)^2+(y-k)^2=r^2 where ( h,k) is the center and r is the radius

(x-0)^2+(y-0)^2=4^2

The center is (0,0) and the radius is 4

4 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- see attachment for the generated data

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

HELP FAST FAST FAST

Rus_ich [418]

Answer:

h=3in

Step-by-step explanation:

A=a+b

Solving forh

h=2A

a+b=2·13.5

3+6=3in

3 0

3 years ago

Pls help will give brainliest when i can ​

Pls help will give brainliest when i can