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creativ13 [48]
3 years ago
11

WORKSHI DIRECTIONS: WERE INACCESSIBLE TRAVERSE AECFA WAS RUN WITH OFFSETS TO THE INACCESSIBLE POINTS. THE FOLLOWING SKETCH SHOWS

A COMPILATION OF THE FIELD NOTES OF A SURVEY. POINTS BAND D CLOSE THE TRAVERSE AND MAKE ANY NECESSARY ADJUSTMENTS AND DETERMINE THE DIMENSIONS AND AREA OF THE TRACT. PTA: N=10000, E=10000 B DUE DATE: 23_2031 119.44'14" E 90°10'10' N0,000 50 N 85°03'53" E 1205.88 A 89'36'36' 1428.43 1221.98 100•07'29" 80°05'45 F 128°14'48 1219.55' C 180.71 D PAGE 1 OF 1 C:\1-CLASS FILESICT-122WORKSHEETS WORKSHEET 6-08.DOCX 01/03/2013​
Engineering
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

is it to late  now

Explanation:

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igor_vitrenko [27]

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Which of the following color schemes is composed of hues next to eachother on the color wheel ?
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If the head loss in a 30 m of length of a 75-mm-diameter pipe is 7.6 m for a given flow rate of water, what is the total drag fo
Stolb23 [73]

Answer:

526.5 KN

Explanation:

The total head loss in a pipe is a sum of pressure head, kinetic energy head and potential energy head.

But the pipe is assumed to be horizontal and the velocity through the pipe is constant, Hence the head loss is just pressure head.

h = (P₁/ρg) - (P₂/ρg) = (P₁ - P₂)/ρg

where ρ = density of the fluid and g = acceleration due to gravity

h = ΔP/ρg

ΔP = ρgh = 1000 × 9.8 × 7.6 = 74480 Pa

Drag force over the length of the pipe = Dynamic pressure drop over the length of the pipe × Area of the pipe that the fluid is in contact with

Dynamic pressure drop over the length of the pipe = ΔP = 74480 Pa

Area of the pipe that the fluid is in contact with = 2πrL = 2π × (0.075/2) × 30 = 7.069 m²

Drag Force = 74480 × 7.069 = 526468.1 N = 526.5 KN

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