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Radda [10]
3 years ago
10

The ______ cycle begins with the new moon.

Engineering
1 answer:
Arisa [49]3 years ago
6 0

Answer:

lunar

Explanation:

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A column in a building is subjected to the following load effects:
vagabundo [1.1K]

Answer:

attached below

Explanation:

6 0
3 years ago
The thrust F of a screw propeller is known to depend upon the diameter d,speed of advance \nu ,fluid density p, revolution per s
musickatia [10]

Answer:

<em>screw thrust = ML</em>T^{-2}<em> </em>

Explanation:

thrust of a screw propeller is given by the equation = pV^{2}D^{2} x \frac{ND}{V}Re

where,

D is diameter

V is the fluid velocity

p is the fluid density

N is the angular speed of the screw in revolution per second

Re is the Reynolds number which is equal to  puD/μ

where p is the fluid density

u is the fluid velocity, and

μ is the fluid viscosity = kg/m.s = ML^{-1}T^{-1}

<em>Reynolds number is dimensionless so it cancels out</em>

The dimensions of the variables are shown below in MLT

diameter is m = L

speed is in m/s = LT^{-1}

fluid density is in kg/m^{3} = ML^{-3}

N is in rad/s = LL^{-1}T^{-1} =

If we substitute these dimensions in their respective places in the equation, we get

thrust = ML^{-3}(LT^{-1}) ^{2}L^{2}\frac{T^{-1} L}{LT^{-1} }

= ML^{-3}L^{2}T^{-2}

<em>screw thrust = ML</em>T^{-2}<em> </em>

This is the dimension for a force which indicates that thrust is a type of force

6 0
3 years ago
Why is resume not consistent?
anzhelika [568]
Hehehehehehehehjsjdhsjakdkhdhahajdjdhfhsjjskskfkfjdjdififjsja sishfhsjdj
7 0
3 years ago
During experiments on laser etching of microchips for IBM, a nuclear engineer places a discshaped sample 5 mm in diameter in a v
Andru [333]

Answer:

Steady state temperature is approximately 801K

Explanation:

Detailed explanation and calculation is shown in the images below.

7 0
4 years ago
Evaluate each of the following and express with an appropriate prefix: (a) (430 kg)^2 (b) (0.002 mg)^2, and (c) (230 m)^3
Mekhanik [1.2K]

Answer:

a)0.185g^2

b)4μg^2( Micrograms)

c)12.167hm^3( cubic hectometer)

Explanation:

To solve this problem, we must first use the calculator to solve each of the points, then knowing the number of zeros on the left or on the right, we choose a unit with which it is better to see the unit

A)

(430 kg)^2=184900kg^2=0.185g^2

B)

(0.002 mg)^2=4x10^-6mg^2=4μg( Micrograms)

c)

(230 m)^3=12167000m^3=12.167hm^3( hectometer)

6 0
3 years ago
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