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2 years ago

7. It is the art of drawing solid objects on two-dimensional surfaces.

Physics

1 answer:

pishuonlain [190]2 years ago

7 0

Explanation:

Perspective- the art of drawing solid objects on a two-dimensional surface so as to give the right impression of their height, width, depth, and position in relation to each other when viewed from a particular point.

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A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a

hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

$a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2$

So the magnitude of the total acceleration is

$a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2$

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3 years ago

An object weighs 42.53 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2? Round to the nearest tenth.

enot [183]

42.53/9.83 = 4.3265.... = 4.3

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3 years ago

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A cylinder of gas is at room temperature (20°C). The air conditioner breaks down, and the temperature rises

noname [10]

Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture

Explanation:

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2 years ago

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined t

luda_lava [24]

The horizontal distance traveled by the ball (range of motion) is given by the following equation:

$x= v_{0x} t$

In which $x$ is the range of motion, $v_{0x}$ is the horizontal component of the initial velocity, and $t$ is the time of motion.

First, lets calculate the horizontal component of the initial velocity:

$v_{0x}= v_{0}cos( \alpha)=13.9cos(35)=11.39$

Now, we calculate the time of motion from the equation that described the motion of the ball in the vertical axis:

$y= \frac{1}{2}at^2+ v_{0y}t$

In which $y$ is the position of the ball vertically, $v_{0y}$ is the vertical component of the initial velocity, $a$ is the acceleration in the vertical axis (which is gravity), and $t$ is time of motion.

We want to find the time when the ball lands, hence, when $y=0$ ; so the equation becomes:

$0= \frac{1}{2}at^2+ v_{0y}t=\frac{1}{2}at^2+ v_{0}sin( \alpha )t=\frac{1}{2}(-9.8)t^2+ 13.9sin(35 )t$

We rewrite it a bit more:

$-4.9t^2+7.97t=0$

This is a quadratic equation, so we use the quadratic equation formula to solve for time (we'll get two answers):

$t= -\frac{1}{9.8} [{-7.97}+-\sqrt{(7.97)^2}]$

Clearly, one of the answers is $t=0$ , this is before you kick the ball (it is on the ground), we want the nonzero answer (when it lands) so:

$t= -\frac{1}{9.8} ({-7.97}-7.97})=1.63$

Now, we plug-in the time value to the equation of the motion's range:

$x= v_{0x} t=(11.39)(1.63)=18.57$

The ball will travel 18.57 meters.

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3 years ago

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Which of the following is a scientific question?

scZoUnD [109]

Answer:

Hey

C Which LED screen design is the most energy-efficient?

In physics, we talk about energy, not the best price, or which one looks the best, or if it violates a patent

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3 years ago

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7. It is the art of drawing solid objects on two-dimensional surfaces.​

7. It is the art of drawing solid objects on two-dimensional surfaces.