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pashok25 [27]
3 years ago
8

Help ASAP please & thank you ​

Physics
1 answer:
jasenka [17]3 years ago
7 0

Answer:

I think its A plz tell me if im right

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A wheel that is rotating at 33.3 rad/s is given an angular acceleration of 2.15 rad/s 2. Through what angle has the wheel turned
Neporo4naja [7]

Answer:

The angle through which the wheel turned is 947.7 rad.

Explanation:

initial angular velocity, \omega _i = 33.3 rad/s

angular acceleration, α = 2.15 rad/s²

final angular velocity, \omega_f = 72 rad/s

angle the wheel turned, θ = ?

The angle through which the wheel turned can be calculated by applying the following kinematic equation;

\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\\theta = \frac{\omega_f^2\   -\  \omega_i^2}{2\alpha } \\\\\theta = \frac{(72)^2\   -\  (33.3)^2}{2(2.15)}\\\\\theta = 947.7 \ rad

Therefore, the angle through which the wheel turned is 947.7 rad.

5 0
3 years ago
There are three states of ………….
erica [24]
There are three states of matter.

5 0
4 years ago
Air "breaks down" when the electric field strength reaches 3×106n/c, causing a spark. a parallel-plate capacitor is made from tw
aalyn [17]
Ok, I think this is right but I am not sure:
 Q = ϵ
 0AE
A= π π
 r^2

=(8.85x10^-12 C^2/Nm^2)
( π π (0.02m)^2)
(3x10^6 N/C) =3.3x10^-8 C = 33nC N = Q/e = (3.3x10^-8 C)/(1.60x10^-19 C/electron) = 2.1x10^11 electrons


4 0
3 years ago
A 3.75 kg ball is lifted from the floor to a height of 1.5 m above the floor. What is its increase in potential energy?
inysia [295]
<span>We can use a simple equation to calculate the increase in gravitational potential energy. PE = mgh m is the mass of the object g is the acceleration due to gravity h is the change in height PE = mgh PE = (3.75 kg) (9.80 m/s^2) (1.5 m) PE = 55.1 Joules The increase in gravitational potential energy is 55.1 Joules.</span>
4 0
3 years ago
The magnitude of the magnetic field at point P for a certain electromagnetic wave is 2.12 μT. What is the magnitude of the elect
valkas [14]

Answer:

The electric field is  E =  636 \ V/m

Explanation:

From the question we are told that

     The magnitude of magnetic field is B  =  2.12 \mu T  =  2.12*10^{-6} \ T

      The value for speed of light is  c =  3.0 *10^8 \ m/s

Generally the magnitude of the electric field at point P is

        E =  B * c

substituting values

         E =  2.12 *10^{-6} *  3.0 *10^{8}

         E =  636 \ V/m

8 0
3 years ago
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