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Andrew [12]
3 years ago
10

What is the reading shown in millimetre​

Physics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

3mm

Explanation:

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Centripetal acceleration depends directly on the square of the object's speed and inversely on
11Alexandr11 [23.1K]

Answer:

True.

Explanation:

The formula for the centripetal acceleration of an object can be calculated by the formula as follows :

a_c=\dfrac{v^2}{r}

Where

v is the speed of an object

r is the radius of the circle

It means, the centripetal acceleration depends directly on the square of the object's speed and inversely on  the radius of the circle. Hence, the given statement is true.

8 0
3 years ago
A 1-hectare field contains 2500 bean plants having a total leaf surface area of 557 m2. ambient temperature is 21°c, winds are
Mashcka [7]

Answer:

The field losses a total of 55.814 litres of water in an hour.

Explanation:

As the complete question is not given here, the average rate of water loss is not given here which is found in normal conditions as 1.67 mL/m2.

Now the average rate of water loss per minute is 1.67 mL/m2

So the average rate of water loss per minute for 557 m2 is 1.67*557=930.19 mL

So 930.19 mL of water is lost from the field in 1 minute, for the calculation of water lost in an hour, the value is given as  60*930.19 =55811.4 mL or 55.814 litres.

8 0
4 years ago
Charles Darwin developed the theory of __________.
Veronika [31]
The answer is natural selection on edge.
8 0
3 years ago
Read 2 more answers
If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?
olya-2409 [2.1K]
Given: Mass m = 44 Kg;      Velocity v = 10 m/s

Required: Kinetic energy K.E = ?

Formula: K.E = 1/2 mv²

               K.E 1/2 (44 Kg)(10 m/s)²

               K.E = 2,200 Kg.m²/s²

               K.E = 2,200 J Answer is A
8 0
3 years ago
Two male moose charge at each other with the same speed and meet on a icy patch of tundra. as they collide, their antlers lock t
yanalaym [24]
Their linear inertia is equivalent to their masses. Let the inertia of the first moose be m₁ and the second be m₂.

m₁u + m₂u = (m₁ + m₂) x 1/3 u
3m₁ + 3m₂ = m₁ + m₂
3 m₁/m₂ + 3 = m₁/m₂ + 1
m₁/m₂ = 2

The ratio of their inertias is 2
7 0
3 years ago
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