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viva [34]
3 years ago
13

If a letter is chosen at random for the word “SUCCESS”, what is the probability that the letter will be C?

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0

<em>Answer</em><em>:</em>

<em>2</em><em> </em><em>out</em><em>. </em><em>of</em><em> </em><em>7</em>

<em>Explanation</em><em>:</em>

<em>First</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>There</em><em> </em><em>are</em><em> </em><em>2</em><em> </em><em>C</em><em> </em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>word</em><em> </em><em> </em><em>and</em><em> </em><em>so</em><em> </em><em>it's</em><em> </em><em>going </em><em>to </em><em>be</em><em> </em><em>2</em><em> </em><em>out</em><em> </em><em>of </em><em>the</em><em> </em><em>total</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>words </em><em>in</em><em> </em><em>the</em><em> </em><em>given </em><em>word</em>

<em>2</em><em> </em><em>/</em><em> </em><em>7</em><em> </em>

<em>So </em><em>that</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>probab</em><em>ility</em><em> </em>

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On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.
Morgarella [4.7K]

Answer:

The actual distance between the historical markers is 18 miles.

Step-by-step explanation:

Given : On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.  

To find : What is the actual distance between the historical markers?

Solution :

We have given that,

2.5 inches represents 10 miles.

i.e, 1 inch represent \frac{10}{2.5} miles.

1 inch = 4 miles.

Now, The distance between two historical markers is 4.5 inches.

The actual distance between the historical markers in 4.5 inch is

4.5 \text{ inch}=4.5\times 4\text{ miles}

4.5 \text{ inch}=18\text{ miles}

Therefore, The actual distance between the historical markers is 18 miles.

7 0
4 years ago
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Which chart belong with the graph at the right?
agasfer [191]

Answer:

Chart nº 2

Step-by-step explanation:

Just match each points you will see which one is actually on the diagram!

6 0
3 years ago
the grocery store has a special deal on potato chips where if you buy 1 bag you get the second bag for 50% off. if the sales tax
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3 years ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

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●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Let's simplify step-by-step.

root^2 + root^{32} + root^{64}

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Have a great day/night!

❀*May*❀

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