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3 years ago

Use the discriminant to determine the number of real solutions to the equation, 10n^2 = 10 - 8n

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

2 real solutions

Step-by-step explanation:

Get all the terms to one side

10n^2 = 10 - 8n

10n^2 +8n -10 =0

ax^2 +bx+c =0

The discriminant is

b^2 -4ac

8^2 - 4(10)(-10)

64 +400

464

If the discriminant is greater than 0 we have 2 real solutions

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3 years ago

A customer went to a garden shop and bought some potting soil for $12.50 and 5 shrubs. The total bill was $62.50. Write and solv

lesya692 [45]

Answer: Equation: $5x = 62.50 - 12.50$ or $x = \frac{62.50-12.50}{5}$

x is the cost of each shrub x = $10

Step-by-step explanation: Total bill = $62.50.

Subtract the cost of potting soil for $12.50 to find the cost of just the shrubs. 5x equals that amount

5x = 62.50 - 12.50

5x = 50 divide both sides by 5

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3 years ago

Look at the following graph of the given equation. Determine whether the equation is a function. Explain why or why not.

Vadim26 [7]

The equation $y=2x+2$ is a function

Explanation:

Given that the graph contains the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$

We need to determine whether the equation $y=2x+2$ is a function.

To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.

Let us substitute the coordinate $(-1,0)$ in the equation $y=2x+2$

Thus, we have,

$0=2(-1)+2$

$0=-2+2$

$0=0$

Thus, the coordinate $(-1,0)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(0,2)$ in the equation, we have,

$2=2(0)+2$

$2=2$

Thus, the coordinate $(0,2)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(1,4)$ in the equation $y=2x+2$

$4=2(1)+2$

$4=4$

Thus, the coordinate $(1,4)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(2,6)$ in the equation, we get,

$6=2(2)+2$

$6=6$

Thus, the coordinate $(2,6)$ satisfies the equation $y=2x+2$

Hence, the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$ satisfies the equation $y=2x+2$

Thus, the equation $y=2x+2$ is a function.

6 0

3 years ago

Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago

Andrea had 32 problems to do for mathematics homework over a weekend. She did of the problems on Friday night, and on Saturday s

Arada [10]

Answer:

first dvide 32 by 3

Step-by-step explanation:

8 0

3 years ago