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adoni [48]
3 years ago
6

What number should go in the space? Multiplying by 0.89 is the same as decreasing by _____%.

Mathematics
2 answers:
Ivan3 years ago
5 0

Answer:

89% is the answer. So goodluck

Solnce55 [7]3 years ago
5 0

Answer:

11%

Step-by-step explanation:

1 - 0.89 = 0.11 which is 11%

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−r3≤6<br> The solution is
lawyer [7]

Answer:

r>=-3

Step-by-step explanation:

4 0
3 years ago
What is the slope of the line that contains the points (-1,2) and (4,3)
Bad White [126]

Answer:

1/5

Step-by-step explanation:

We can find the slope using the slope formula

m = (y2-y1)/(x2-x1)

   = (3-2)/(4 - -1)

   (3-2)/(4+1)

    1/5

4 0
3 years ago
During exercise Sonia's heart beats 675 times in 5 minutes. How many times does it beat per minute?
Kaylis [27]


135 times because 675 divided by 5 is 135. you would divide the number of her heart beats by the number


3 0
3 years ago
Read 2 more answers
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l
tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

<u><em>Step(ii):-</em></u>

<u><em>The Empirical rule</em></u>

         Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

        Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }

       Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

    P(X⁻ ≥ 96.3) = P(Z≥2.383)

                      =  1- P( Z<2.383)

                      =  1-( 0.5 -+A(2.38))

                      = 0.5 - A(2.38)

                     = 0.5 -0.4913

                    = 0.0087

<u><em>Final answer:-</em></u>

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0
3 years ago
A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine co
seraphim [82]

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

7 0
3 years ago
Read 2 more answers
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