Answer:
2√2 / 3 (first answer choice)
Step-by-step explanation:
If tan Ф < 0, then Ф must be in either Quadrant II or Quadrant IV.
If sin Ф = +1/3, then Ф (for this problem) is in Quadrant II.
Remembering that sin Ф = opp / hyp = 1 / 3, we use the Pythagorean Theorem to find the adj side:
adj² + 1² = 3², or
adj² + 1 = 9, or adj² = 8. Since Ф is in Quadrant II, adj is negative.
The value of cos Ф = adj / hyp = √8 / 3 = 2√2 / 3
Answer:
The student's mean score in the class is 80.6
Step-by-step explanation:
we know that
To find out the student's mean score in the class, multiply each score by its worth and adds the numbers
therefore
The student's mean score in the class is 80.6
Answer:
one-sixth of 138
Step-by-step explanation:
36÷3=12. 138÷6=23
12<23
Therefore, one-sixth of 138 is greater than a third of 36.
Dear!
In my best knowledge,your ans is b.
The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3
Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
Evaluated with x means that</span> x = 3.
f(3) = 3² + 2 * 3 = 9 + 6 = 15
15 ≠ 3, so, this is not correct.
2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
Evaluated with -3 means that x = -3.
(f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18
18 ≠ 3, so, this is not correct.
3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span> Evaluated with -3 means that x = -3.
f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
3 = 3, so this is correct.
4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
Evaluated with 3 means that x = 3.
f(3) = (3)² - 3 * 3 = 9 - 9 = 0
0 ≠ 3, so this is not correct.
