Density = 2.7g/cm3
mass =8.1grams
from density =(mass)/volume
we can determine the volume of aluminium by simply changing the subject of the subject of the formula from density to volume
so we have
volume=mass/density
=(8.1grams)/(2.7g/cm3)
=3cm3
Answer:
a. Gamma ray, microwaves, infrared
The vertical component of
this acceleration will be:
A= mgsin^2 <span> θ</span>
The downward fforce exerted by the hamster on the block and
on the scle will be
F = -ma
The reading will be like this:
Reading = Mg + mg sin^2 θ
= (0.820) (9.8) +
(0.190) (9.8) sin^2 (0)
<span>Reading = 8.036 N</span>
Answer:
X = 2146.05 m
Explanation:
We need to understand first what is the value we need to calculate here. In this case, we want to know how far from the starting point the package should be released. This is the distance.
We also know that the plane is flying a certain height with an specific speed. And the distance we need to calculate is the distance in X with the following expression:
X = Vt (1)
However we do not know the time that this distance is covered. This time can be determined because we know the height of the plain. This time is referred to the time of flight. And the time of flight can be calculated with the following expression:
t = √2h/g (2)
Where g is gravity acceleration which is 9.8 m/s². Replacing the data into the expression we have:
t = √(2*2500)/9.8
t = 22.59 s
Now replacing into (1) we have:
X = 95 * 22.59
<h2>
X = 2146.05 m</h2>
This is the distance where the package should be released.
Hope this helps
The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration <em>a</em> of
950 N = (2300 kg) <em>a</em>
<em>a</em> = (950 N) / (2300 kg)
<em>a</em> ≈ 0.413 m/s²
Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of
<em>v</em> = -5.5 m/s + <em>a</em> (11.5 s)
<em>v</em> = -0.75 m/s
which means the wind slows the boat down to a velocity of 0.75 m/s westward.