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Tanya [424]
3 years ago
8

Identify the statement below that is true about a type of stress.

Physics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

These are my answers hope helps)

1.D

2.B

3.A

Explanation:

Sunny_sXe [5.5K]3 years ago
6 0

1-D Eustress is a positive response

2-B resistance

3-A Imagine you are doing your gymnastics

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A small, 3 kg weight is moved from 5 m from the ground to 8 m. What is the change in potential energy?
Ulleksa [173]

Answer: 88.2 J

Explanation: PE, OR Potential Energy, equals to mass gravity and height.

mass - 3kg

height - 3 because (8-5)

gravity is 9.8kg

so 3 times 3 times 9.8 = 88.2J

4 0
4 years ago
What is the Force in Newtons exerted by cart with a mass of 0.75 kg and an Acceleration of 6m/s2?
denis-greek [22]

Answer:

<h2>4.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.75 × 6 = 4.5

We have the final answer as

<h3>4.5 N</h3>

Hope this helps you

6 0
2 years ago
A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following fun
snow_lady [41]

The correct answer would be  1.375 < t < 3  i hope this helps anyone


8 0
3 years ago
Read 2 more answers
How long would it take for Sofia to walk 300 meters if she is walking at a velocity of 2.5 m/s?
Vaselesa [24]

Answer:

Time=120seconds

Explanation:

S=300m

V=2.5m/s

t=?

V=S/t

t=S/V

t=300/2.5

t=120 second

7 0
4 years ago
Read 2 more answers
A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

-a = 5

a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

F = 3 x 5

F = 15 N

Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
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