A parallel-plate air capacitor with a capacitance of 240pF has a charge of magnitude 0.146uC on each plate. The plates have a se
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We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
From the question we are told
- Two go carts, A and B race each other around a 1.0 km track.
- Go cart A travels at a constant speed of 20.0 m/s.
- Go cart B accelerates uniformly from rest at a rate of 0.333 m/s
For Cart A
Generally the equation for the Velocity is mathematically given as
For Cart B
Generally the Newtons equation for the Motion is mathematically given as
Since
Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
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The equation you need to use is 
where Q is the charge in C, I is the current in Amps and T is the time in seconds.
So we have T = 60s
I =
A
let's work out Q
C
this is the total charge passing a point in a minute so divide by the charge of one electron (
) to find the number of electrons passing the point in a minute which equals 
So we have T = 60s
I =
let's work out Q
this is the total charge passing a point in a minute so divide by the charge of one electron (