1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreyandreev [35.5K]
3 years ago
11

Is neon neutral and stable or unstable?

Chemistry
2 answers:
liubo4ka [24]3 years ago
6 0

Answer:

neon is stable

Explanation:

beacuse it has a full octet or valence shell of 8 electrons

brainliest please:) i hope you have a nice day

Evgen [1.6K]3 years ago
6 0
Neon is one of the most stable and least reactive elements due to having full valence shells
You might be interested in
The dipole measured for HI is 0.380 D. The bond distance is 161 pm. What is the percent ionic character of the HI bond?
Feliz [49]

Answer:

Percent ionic character of HI bond is 4.91%.

Explanation:

<h3>Given Data:</h3>

Measured Dipole = 0.380D

bond distance = d = 161pm = 1.61*10^-8 cm

<h3>Calculation:</h3>

% ionic character is determined by following equation:

% ionic= (dipole measured/dipole calculated)*100

Now,

Dipole(calc)=qd

Dipole(calc)= (1.6*10^{-19}*3*10^{9})esu  *1.61*10^{-8}cm

(In above step 3*10^8 is multiplied to convert coulomb into esu)

Dipole(calc)=7.728*10^{-18} esu*cm

As,

10^{-18}esu*cm= 1D

So,

Dipole(calc)=7.728D

Now we can % ionic character using above equation:

%ionic=(0.380D/7.728D)*100

% ionic character=4.91%

5 0
4 years ago
The chemistry of nitrogen oxides is very versatile. Given the following reactions and their standard enthalpy changes, (1) NO(g)
AVprozaik [17]

Answer:

The heat of reaction for N₂O₃(g) + N₂O₅(s) → 2 N₂O₄(g) is ΔH = -22.2 kJ

Explanation:

Given the following reactions and their standard enthalpy changes:

(1) NO(g) + NO₂(g) → N₂O₃(g) ΔH o rxn = −39.8 kJ

(2) NO(g) + NO₂(g) + O₂(g) → N₂O₅(g) ΔH o rxn = −112.5 kJ

(3) 2 NO₂(g) → N₂O₄(g) ΔH o rxn = −57.2 kJ

(4) 2 NO(g) + O₂(g) → 2 NO₂(g) ΔH o rxn = −114.2 kJ

(5) N₂O₅(s) → N₂O₅(g) ΔH o subl = 54.1 kJ

You need to get the heat of reaction from: N₂O₃(g) + N₂O₅(s) → 2 N₂O₄(g)

Hess's Law states: "The variation of Enthalpy in a chemical reaction will be the same if it occurs in a single stage or in several stages." That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when verified in a single stage.

This law is the one that will be used in this case. For that, through the intermediate steps, you must reach the final chemical reaction from which you want to obtain the heat of reaction.

Hess's law explains that enthalpy changes are additive. And it should be taken into account:

  • If the chemical equation is inverted, the symbol of ΔH is also reversed.
  • If the coefficients are multiplied, multiply ΔH by the same factor.
  • If the coefficients are divided, divide ΔH by the same divisor.

Taking into account the above, to obtain the chemical equation

N₂O₃(g) + N₂O₅(s) → 2 N₂O₄(g)  you must do the following:

  • Multiply equation (3) by 2

(3) 2*[2 NO₂(g) → N₂O₄(g) ] ΔH o rxn = −57.2 kJ*2

<em>4 NO₂(g) →  2 N₂O₄(g)  ΔH o rxn = −114.4 kJ</em>

  • Reverse equations (1) and (2)

(1) <em>N₂O₃(g)  → NO(g) + NO₂(g) ΔH o rxn = 39.8 kJ</em>

(2) <em>N₂O₅(g) →  NO(g) + NO₂(g) + O₂(g)  ΔH o rxn = 112.5 kJ</em>

Equations (4) and (5) are maintained as stated.

(4) <em>2 NO(g) + O₂(g) → 2 NO₂(g) ΔH o rxn = −114.2 kJ </em>

(5) <em>N₂O₅(s) → N₂O₅(g) ΔH o subl = 54.1 kJ </em>

The sum of the adjusted equations should give the problem equation, adjusting by canceling the compounds that appear in the reagents and the products according to the quantity of each of them.

Finally the enthalpies add algebraically:

ΔH= -114.4 kJ + 39.8 kJ + 112.5 kJ -114.2 kJ + 54.1 kJ

ΔH= -22.2 kJ

<u><em>The heat of reaction for N₂O₃(g) + N₂O₅(s) → 2 N₂O₄(g) is ΔH = -22.2 kJ</em></u>

8 0
3 years ago
Convert 45 joules to heat calories
skad [1K]

Answer:

45 joules to calories= 10 (10.755258) calories

3 0
4 years ago
In general, the Hippocratic Oath requires physicians to do all of the following EXCEPT which action?
AysviL [449]

Answer:

Physicians do not have to treat every ill patient. However they must uphold their ethics (eg. do no harm, confidentiatlity, etc.).

Explanation:

Primary source:

Hippocratic Oath (translation since it's originally in Greek)

I swear by Apollo the physician, and Asclepius, and Hygieia and Panacea and all the gods and goddesses as my witnesses, that, according to my ability and judgement, I will keep this Oath and this contract:

To hold him who taught me this art equally dear to me as my parents, to be a partner in life with him, and to fulfill his needs when required; to look upon his offspring as equals to my own siblings, and to teach them this art, if they shall wish to learn it, without fee or contract; and that by the set rules, lectures, and every other mode of instruction, I will impart a knowledge of the art to my own sons, and those of my teachers, and to students bound by this contract and having sworn this Oath to the law of medicine, but to no others.

I will use those dietary regimens which will benefit my patients according to my greatest ability and judgement, and I will do no harm or injustice to them.

I will not give a lethal drug to anyone if I am asked, nor will I advise such a plan; and similarly I will not give a woman a pessary to cause an abortion.

In purity and according to divine law will I carry out my life and my art.

I will not use the knife, even upon those suffering from stones, but I will leave this to those who are trained in this craft.

Into whatever homes I go, I will enter them for the benefit of the sick, avoiding any voluntary act of impropriety or corruption, including the seduction of women or men, whether they are free men or slaves.

Whatever I see or hear in the lives of my patients, whether in connection with my professional practice or not, which ought not to be spoken of outside, I will keep secret, as considering all such things to be private.

So long as I maintain this Oath faithfully and without corruption, may it be granted to me to partake of life fully and the practice of my art, gaining the respect of all men for all time. However, should I transgress this Oath and violate it, may the opposite be my fate.

8 0
3 years ago
How is an average mass different from a weighted average mass?
34kurt
<span>With any element, there are a range of isotopes . . . a weighted average mass is used because there exist different isotopes of that element, each of varying mass.  A weighted average accounts for the fact that the average mass (that may likely be measured from a random sample of the element) will most likely reflect the average mass of the more abundant isotopes.  So the weighted average mass will be most comparable to the more abundant isotopes.</span>
4 0
3 years ago
Read 2 more answers
Other questions:
  • Electrons have almost no mass. True False
    8·2 answers
  • KNO3(s) --&gt; K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
    14·1 answer
  • 1s
    5·1 answer
  • An isotope undergoes radioactive decay. The new isotope that forms has an atomic number that is 2 less than the original isotope
    5·2 answers
  • The quantity of antimony in a sample can be determined by an oxidation–reduction titration with an oxidizing agent.
    8·2 answers
  • A 150.0 mL sample of 0.20 M HF is titrated with 0.10 M LiOH. Determine the pH of the solution after the addition of 600.0 mL of
    9·1 answer
  • What do you notice with your answer​
    12·1 answer
  • If the abundance of ​ 85​ Rb is 72.2% and the abundance of 87​ Rb is 27.8%, what is the average atomic mass of rubidium?
    7·1 answer
  • Classify these compounds as acid, base, salt, or other. Drag the appropriate items to their respective bins.
    9·2 answers
  • Help! This has to be done by time I wake up for school I need to know How many calories
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!