Answer:
option C.there is an accumulation of carbon dioxide.
Explanation:
Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
The element cesium forms a positive ion with the charge +1 . The symbol for this ion is Ce⁺, and the name is cesium ion. The number of electrons in this ion is 54.
<h3>What group does the element cesium belong to in the periodic table?</h3>
Cesium belong to the Group 1A of the periodic table.
Group 1A elements are known as alkali metals.
The alkali metals react with water to form alkalis. They form ions with a positive charge of +1 by the loss of an electron.
In conclusion, cesium is an alkali metals it belongs to group 1A of the periodic table. It forms a positive ion with a charge of +1 by the loss of an electron.
Learn more about alkali metals at: brainly.com/question/25317545
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I1f calcium lost 2 electrons, it would have the same number of electrons as Argon.
Answer: there is nothing there to answer
Explanation:
