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3 years ago

A bowling ball of 35.2kg, generates 218 kg.m/s units of momentum. What is the velocity of the bowling ball?

Physics

1 answer:

KIM [24]3 years ago

7 0

Answer:

6.19m/s

Explanation:

Given parameters:

Mass of bowling ball = 35.2kg

Momentum = 218kgm/s

Unknown:

Velocity of the bowling ball = ?

Solution:

Momentum is the quantity of motion a body possess;

Momentum = mass x velocity

218 = 35.2 x velocity

Velocity = 6.19m/s

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3 years ago

g What is the specific heat of silver? The molar heat capacity of silver is 25.35 J/mol⋅∘C. How much energy would it take to rai

disa [49]

Answer:

38.6 J

Explanation:

c = molar heat capacity of silver = 25.35 J/(mol °C)

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Number of moles of silver are given as

$n=\frac{m}{M}$

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3 years ago

A long jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. Assuming he can

GenaCL600 [577]

Answer:

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

$v$ = speed at which jumper jumps at all time

initial distance jumped is given as

$R_{1}=\frac{v^{2}Sin2\theta _{1} }{g}$

final distance jumped is given as

$R_{2}=\frac{v^{2}Sin2\theta _{2} }{g}$

Dividing final distance by initial distance

$\frac{R_{2}}{R_{1}}=\frac{Sin2\theta _{1}}{Sin2\theta _{2}}$

$\frac{R_{2}}{7.4}=\frac{Sin2(42.9)}{Sin2(45))}$

$R_{2} =7.38$

distance lost is given as

d = $R_{1} - R_{2}$

d = 7.4 - 7.38

d = 0.02 m

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3 years ago