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3 years ago

8

How did you figure that out? (think of FORMULA!)

1 answer:

Minchanka [31]3 years ago

5 0

Answer:

the most potential energy would be at the highest point and the least it's at the lowest point so let's say and rollercoaster when it's like moving up its gaining potential energy while it's going down it loses potential energy (sorry if u get it wrong)

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An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. What is the minimum coef

navik [9.2K]

An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. The minimum coefficient of static friction needed for this claim to be possible is 0.7

In an inclined plane, the coefficient of static friction is the angle at which an object slide over another.

As the angle rises, the gravitational force component surpasses the static friction force, as such, the object begins to slide.

Using the Newton second law;

$\sum F_x = \sum F_y = 0$

$\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }$

So; On the L.H.S

$\mathbf{mg sin \theta =f_s}$

$\mathbf{mg sin \theta =\mu_s N}$

On the R.H.S

N = mg cos θ

Equating both force component together, we have:

$\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}$

$\mathbf{sin \theta =\mu_s \ \ cos \theta}$

$\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}$

From trigonometry rule:

$\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}$

∴

$\mathbf{\mu_s =\tan \theta}}$

$\mathbf{\mu_s =\tan 35^0}}$

$\mathbf{\mu_s = 0.700}}$

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

Learn more about static friction here:

brainly.com/question/24882156?referrer=searchResults

8 0

3 years ago

ANSWER THIS QUESTION!!!! PLSSSSS!!! NEED HELP!!!!! 10 POINTS

Olegator [25]

Answer:

A. it's the only answer that makes sense. if I'm wrong sorry

6 0

3 years ago

A ball falls from a shelf. Assuming there is no friction, why is the conservation of mechanical energy independent of mass?(1 po

cluponka [151]

Answer:

It's B

Explanation:

Hope this helps, tell me if im wrong!

5 0

2 years ago

Read 2 more answers

Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

Zinaida [17]

Answer:

r = 1.61 x 10^{11} m

Explanation:

energy radiated (H) = 2.7 x 10^31 W

surface temperature (T) = 11,000 k

assuming ε = 1 and taking σ = 5.67 x 10^{-8} W/m^{2}.K^{4}

we can find the radius of the star from the equation below

H = A x ε x σ x T^{4}

where area (A) = 4 x π x r^{2} (assuming it is a sphere)

therefore the equation becomes

H = 4 x π x r^{2} x ε x σ x T^{4}

2.7 x 10^31 = 4 x π x r^{2} x 1 x 5.67 x 10^{-8} x (11,000)^{4}

r = $\sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8} x (11,000)^{4}} }$

r = 1.61 x 10^{11} m

4 0

3 years ago

8. Express 2.69 x 10^9 in standard form.

taurus [48]

Answer:

242.1

Explanation:

10 x 9 equals 90

2.69 x 90 = 242.1

5 0

3 years ago