1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gogolik [260]
3 years ago
8

How did you figure that out? (think of FORMULA!)

Physics
1 answer:
Minchanka [31]3 years ago
5 0

Answer:

the most potential energy would be at the highest point and the least it's at the lowest point so let's say and rollercoaster when it's like moving up its gaining potential energy while it's going down it loses potential energy (sorry if u get it wrong)

You might be interested in
A hydrogen bond forms by the electrostatic interaction of opposite charges in two molecules. If
Darya [45]

The force between the molecules involved in the bond is 6. 426 *10^-11 Newton

<h3>How to determine the force</h3>

Using the formula:

F = K[q1 x q2]/D^2

where K is coulombs constant =9 *10 ^9 Nm^2/C^2.

q1  and q2 = charges  =  1.60x10 -20C

d = distance between the charges = 2x10 -10 m

Substitute the values into the formula

F =  9 * 10^9\frac{ 1.60*10^ -20 *  1.60 *10^ -20}{2x10^ -10^{2} }

F = 9 *10^9\frac{2. 856* 10^-40}{4* 10^-20}

F = 9* 10^9 * 7. 14* 10^-21

F = 6. 426 * 10^-11 Newton

Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton

Learn more about electrostatic force here:

brainly.com/question/8424563

#SPJ1

5 0
2 years ago
The following graph shows the force exerted on and the displacement of object being pulled
Tomtit [17]

The work done to pull the object 7.0 m is the total area under the graph from 0.0 m to 7.0 m, determined as 245 J.

<h3>Work done by the applied force</h3>

The area under force versus displacement graph is work done.

The total work done by pulling the object 7 m, can be grouped into two areas;

  • First area, A1 = area of triangle from 0 m to 2.0 m
  • Second area, A2 = area of trapezium, from 2.0 m to 7.0 m

A1 = ¹/₂ bh

A1 = ¹/₂ x (2) x (20)

A1 = 20 J

A2 = ¹/₂(large base + small base) x height

A2  = ¹/₂[(7 - 2) + (7-3)] x 50

A2 = ¹/₂(5 + 4) x 50

A2 = 225 J

<h3>Total work done </h3>

W = A1 + A2

W = 20 J + 225 J

W = 245 J

Learn more about work done here: brainly.com/question/8119756

3 0
2 years ago
. The naturally occurring charge on the ground on a fine day out in the open country is –1.00nC/m2 . (a) What is the electric fi
JulijaS [17]

Answer:

a) -113 N/C

b) -423.71 V

Explanation:

The Step by step explanation and solution has been attached in the attachment section.

4 0
3 years ago
The process of _____________ is modeled in the plant cell diagrams seen here. A) osmosis B) tonicity C) active transport D) faci
Andrej [43]

dAnswer:

Explanation:

5 0
3 years ago
Read 2 more answers
Select the correct answer.
Natali [406]

its b hoped i helped

8 0
3 years ago
Read 2 more answers
Other questions:
  • Tala wants to create a sound echo. She can create the echo using a pane of glass or a carpet square. Which one does she choose?
    14·1 answer
  • ________________________ energy is the energy that an object gets from its position and motion. Question 2 options: mechanical n
    13·1 answer
  • According to Newton's first law of motion, what will an object in motion do when
    12·2 answers
  • Matter that emits no light at any wavelength is called
    11·2 answers
  • What drives people to explore
    12·1 answer
  • Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to
    8·1 answer
  • Cold water flows to the solar panels at 15°C. During the day, the panels supply 3.8 kg of hot water
    14·1 answer
  • Water being put in a freezer will go through what phase change?
    14·1 answer
  • A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the
    10·1 answer
  • I dont understand pojectile motion can someone help with this
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!