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Solnce55 [7]
3 years ago
5

a student throws a coin vertically downward frok the top of a building. the coin leaves the throwers hand with a speed of 15.0m/

s. what is its speed after falling freely for 2.00s?​
Physics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

Final speed after 2 seconds = 34.6 m/s

Explanation:

Given:

Initial speed of coin (u) = 15 m/s

Time taken = 2 seconds

Find:

Final speed after 2 seconds

Computation:

Gravitational acceleration of earth = 9.8 m/s²

Using first equation of motion;

v = u + at

or

v = u + gt

where,

v = final velocity

u = initial velocity

g = Gravitational acceleration

t = time taken

v = 15 + 9.8(2)

v = 15 + 19.6

Final speed after 2 seconds = 34.6 m/s

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Answer:

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Given,

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Answer:

<h3>62.5N</h3>

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Cross product may be observed with the aid of using

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wherein i represents the +x route, j represents the +y route and okay represents the +z route

The RIGHT HAND RULE may be used to demonstrate the move product with the aid of using the usage of the proper hand and pointing the index finger withinside the route of the primary vector and the center finger alongside the second one vector, the move product is withinside the route of the thumb.

A) vec Ein the +xdirection,vec Bin the +ydirection,

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D) vec Ein the +y route,vec Bin the -z route

Finding the move made from the 2 vectors (j x - okay = - i) might provide a vector withinside the -x route

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