a student throws a coin vertically downward frok the top of a building. the coin leaves the throwers hand with a speed of 15.0m/
1 answer:
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Answer:
The kinetic energy of box b is 2.44 J.
Explanation:
Given that,
Mass of box a =3.00 kg
Mass of box b=1.00 kg
Distance = 1.00 m
We need to calculate the acceleration of the system
Using formula of acceleration
put the value into the formula
We need to calculate the velocity
Using equation of motion
Put the value into the formula
We need to calculate the kinetic energy of box b
Using formula of energy
Put the value into the formula
Hence, The kinetic energy of box b is 2.44 J.
Answer:
<em>The velocity after the collision is 2.82 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.
After the collision, both cars stick together. Let's compute the common speed after that:
The velocity after the collision is 2.82 m/s