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liraira [26]
3 years ago
8

HELP ITS FOR SCIENCE

Physics
2 answers:
yuradex [85]3 years ago
7 0
For number 2:
Speed is related to kinetic energy because kinetic energy is the energy of motion.

Hope this helped!
Rashid [163]3 years ago
7 0

Answer:

A wrecking ball has the capability to destroy a building due to the greater mass and kinetic energy than the yo-yo.

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Which of the following is the correct relationship among the acceleration, velocity, and position?
Damm [24]

Answer:1

Explanation:

If

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so a=\frac{\mathrm{d} v}{\mathrm{d} t}

multiply and divide by ds

a=\frac{\mathrm{d} v}{\mathrm{d} t}\times \frac{ds}{ds}

a=\frac{\mathrm{d} v}{\mathrm{d} s}\times \frac{\mathrm{d} s}{\mathrm{d} t}

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ads=vdv

option 1 is correct

5 0
3 years ago
Read 2 more answers
Name 3 muscles of the leg​
xxTIMURxx [149]

Answer:

calf

Explanation:

jdjdjddjdjdhdhdj

4 0
3 years ago
Can you help me answer this?
Pavel [41]
The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.
5 0
3 years ago
Two ships leave a harbor at the same time, traveling on courses that have an angle of 110∘ between them. If the first ship trave
Allushta [10]

Answer:

49.07 miles

Explanation:

Angle between two ships = 110° = θ

First ship speed = 22 mph

Second ship speed = 34 mph

Distance covered by first ship after 1.2 hours = 22×1.2 = 26.4 miles = b

Distance covered by second ship after 1.2 hours = 34×1.2 = 40.8 miles = c

Here the angle between the two sides of a triangle is 110° so from the law of cosines we get

a² = b²+c²-2bc cosθ

⇒a² = 26.4²+40.8²-2×26.4×40.8 cos110

⇒a² = 2408.4

⇒a = 49.07 miles

6 0
3 years ago
A car is moving with an initial relocity of
MA_775_DIABLO [31]

Answer:

The final acceleration of the car, v = 70 m/s

Explanation:

Given,

The initial velocity of the car, u = 20 m/s

The acceleration of the car, a = 10 m/s²

The time period of travel, t = 5 s

Using the I equations of motion

                     v = u + at

                        = 20 + 10(5)

                        = 20 + 50

                        = 70 m/s

Hence, the final acceleration of the car, v = 70 m/s

4 0
3 years ago
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