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saw5 [17]
3 years ago
13

What is pure convalent bond

Chemistry
1 answer:
Bad White [126]3 years ago
7 0

Answer:

Pure covalent bonds exist between two atoms with the same electronegativities. A pure covalent bond has no ionic character at all. Diatomic elements are good examples of pure covalent bonds where the electrons are evenly shared between both nuclei.

Explanation:

Hope this helped!

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It is 0 gradus in celcius
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What are some genetic diseases?
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Answer:

Down Syndrome- is when you have an extra 21st chromosome.

Turner Syndrome- is when one of the x chromosome is missing or partly there.

Explanation:

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8 0
4 years ago
A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced.
nata0808 [166]

Answer: 25.37055324733817mol

Approximately 25.371mol

Explanation: Number of moles of a substance is the mass of that substance containing the same amount of fundamental units, for instance atom in 12.0g of 12°C

Therefore:

Number of moles= mass/ molecular mass

Where mass of fluorine given= 482g

Standard Molecular mass of fluorine= 18.9984032g/mol

Substituting value in equation

Mole= 482g/18.9984032g/mol = 25.37055324733817mol

Approximately : 25.371mol

4 0
3 years ago
Drag each label to the correct location on the equation. Each label may be used more than once.
elena-14-01-66 [18.8K]
HCl is an acid, C5H5N is a base, Cl is an acid, and HC5H5N is an acid.

Hope this helps! If so, brainliest would be appreciated!
8 0
2 years ago
Calculate the energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom. E = Joules Is
kramer

Answer:

For an electron to move from a lower energy level to a higher energy , that electron needs to absorb energy sufficient enough to excite it to make the transition. Hence it is an absorption process. The required energy of transition  E = 2.665 x 10⁻²⁰J

Explanation:

Using the Rydberg's equation we can calculate the wavelength of the photon of energy transition as follows:

1/λ = R . (1/nf² - 1/ni²)

where

λ is the required wavelength of the photon needed to be absorbed to excite the electron to transit from level 5 to 6.  

(Note that for the electron to transit to from energy level 5 to 6, the photon would have to fall from level 6 to 5 in order to emit the required energy to excite the electron)

R is the Rydberg's constant 1.097 x 10⁷ m⁻¹

nf is the final level of the photon

ni is the initial level of the photon

1/λ = 1.097 x 10⁷ m⁻¹ (1/5² - 1/6²)

1/λ = 1.3407 x 10⁵ m⁻¹

λ = 7.458 x 10⁻⁶ m

This implies that that is the wavelength of the photon required to excite the electron to transit from energy level 5 to 6. Using the equation below, we can calculate the energy of transition as

E = h.c/λ

where

E is the required energy of transition

h is the Planck's constant (6.626 x 10⁻³⁴ Js)

c is the speed of light (3 x 10⁸ms⁻¹)

λ is the wavelength calculated above

E = 6.626 x 10⁻³⁴ Js  x  3 x 10⁸ms⁻¹/ 7.458 x 10⁻⁶ m

E = 2.665 x 10⁻²⁰J

3 0
3 years ago
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