Question

For the reaction ? Ch3oh+? O2 →? Hco2h+? H2o , what is the maximum amount of hco2h (46.0254 g/mol) which could be formed from 6.95 g of ch3oh (32.0419 g/mol) and 8.11 g of o2 (31.9988 g/mol)? Answer in units of g

Answer 1

Answer:- 9.98 grams.

Solution:- The given balanced equation is:

$CH_3OH+O_2\rightarrow HCO_2H+H_2O$

From this equation, there is 1:1 mol ratio between methanol and formic acid. We start with given grams of methanol and convert them to moles. Then using mol ratio the moles of foramic acid are calculated and finally converted to grams on multiplying by it's molar mass.

The calculations could easily be done using dimensional analysis as:

$6.95gCH_3OH(\frac{1molCH_3OH}{32.0419g})(\frac{1molHCO_2H}{1molCH_3OH})(\frac{46.0254gHCO_2H}{1molHCO_2H})$

= $9.98gHCO_2H$

Hence, 9.98 grams of formic acid can be formed from 6.95 grams of methanol.