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dem82 [27]
3 years ago
10

What is the pH of a 0.222 M acetic acid solution?

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

pH=2.7

<h3>Further explanation</h3>

Acetic acid = weak acid

\tt [H^+]=\sqrt{Ka.M}

Ka = acid ionization constant

M = molarity

Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵

\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}

\tt pH=3-log~1.998=2.7

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Answer : The concentration of Fe^{3+} at equilibrium is 0 M.

Solution :  Given,

Concentration of Fe^{3+} = 0.0200 M

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                            Fe^{3+}(aq)+3C_2O_4^{2-}(aq)\rightleftharpoons [Fe(C_2O_4)_3]^{3-}(aq)

Initially conc.       0.02         1.00                   0

At eqm.             (0.02-x)    (1.00-3x)                x

The expression of K_c will be,

K_c=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[C_2O_4^{2-}]^3[Fe^{3+}]}

1.67\times 10^{20}=\frac{(x)^2}{(1.00-3x)^3\times (0.02-x)}

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x=0.02M

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horrorfan [7]

Answer : (C) Hafnium is the most likely identity of the given substance.

Solution :  Given,

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